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Svetllana [295]
3 years ago
7

A shark is swimming 28 ft below sea level. If the angle of depression from a boat on the water to the shark is 19 degrees, what

is the horizontal distance between the boat and the shark?
Mathematics
1 answer:
Orlov [11]3 years ago
3 0

Answer:

81,3 ft to the nearest tenth.

Step-by-step explanation:

Tan 19 = 28 / h  where h = the horizontal distance.

h = 28 / tan 19

h = 81.3 ft.

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Hunter-Best [27]

Answer:

The length of \overline {FH} is;

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Step-by-step explanation:

The given parameters are;

The type of the given quadrilateral FGHI = Rectangle

The diagonals of the quadrilateral = \overline {FH} and \overline {GI}

The length of IE = 3·x + 4

The length of EG = 5·x - 6

We have from segment addition postulate, \overline {GI} = IE + EG

The properties of a rectangle includes;

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Therefore,  \overline {FH} bisects \overline {GI}, into two equal parts, from which we have;

IE = EG

\overline {GI} = IE + EG

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From which we have;

IE = 3·x + 4 = 3 × 5 + 4 = 19 units

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\overline {GI} = IE + EG = 19 + 19 = 38 units

\overline {GI} = 38 units

2) The lengths of the two diagonals are equal. Therefore, the length of segment \overline {FH} is equal to the length of segment \overline {GI}

Mathematically, we have;

\overline {FH} = \overline {GI} = 38 units

∴ \overline {FH} = 38 units.

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