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ICE Princess25 [194]
4 years ago
10

Solve this problem PLS SOLVE ASAP!!

Mathematics
1 answer:
guajiro [1.7K]4 years ago
8 0
αa^{2} (-4+6)
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Please help! I will mark you as brainliest!
matrenka [14]

Answer:

3.5 hours traveling

2.5 hours stationary

Step-by-step explanation:

When the line is horizontal, the distance isn't changing, so she is stationary, so just add the total time the line is horizontal.

Likewise, all other lines represent traveling.

8 0
3 years ago
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Someone help please?
vladimir2022 [97]

Answer: The slope would be -2, (C) and the Y intercept would be 5

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3 years ago
Which numbers are solutions to the inequality
bija089 [108]

Answer:

this is simply clever goggle lens

Step-by-step explanation:

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5 0
3 years ago
A 25​-foot ladder is placed against a vertical wall of a​ building, with the bottom of the ladder standing on level ground 18 fe
galben [10]
A^2 +b^2 = c^2
a= wall
b = ground (18)
c = ladder (25)
a^2 + 18^2 = 25^2
a^2 + 324 = 625
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a = 17.349
5 0
3 years ago
Please solve i and ii for me
KengaRu [80]

If you know the derivative f'(x) of some function f(x), you can tell exactly who f(x) is, up to an additive, constant term. In fact, knowing f'(x), you have

\displaystyle \int f'(x) = f(x)+c

In your case, we have

\dfrac{d}{dx} \sqrt{x+3} = \dfrac{1}{2\sqrt{x+3}}

So, the integral is almost immediate:

\displaystyle\int \dfrac{2}{\sqrt{x+3}} = \int \dfrac{4}{2\sqrt{x+3}} = 4\int\dfrac{1}{2\sqrt{x+3}} = 4\sqrt{x+3}+c

So, up to some constant additive term, our function is 4\sqrt{x+3}+c

To fix this constant, we know that the function passes through the point (6,10), so we have

f(6) = 4\sqrt{6+3}+c = 4\sqrt{9}+c=12+c=10 \iff c=-2

And so our function is 4\sqrt{x+3}-2

If we want to know when this function equals 6, we simply have to ask f(x)=6 and solve for x, so we have

4\sqrt{x+3}-2=6 \iff 4\sqrt{x+3} = 8 \iff \sqrt{x+3} = 2 \iff x+3=4 \iff x = 1

5 0
3 years ago
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