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lesya [120]
3 years ago
13

Which function is a quadratic function?

Mathematics
1 answer:
DerKrebs [107]3 years ago
5 0
The correct answer is: [C]:  " c(x) = –8x²<span> + 3x – 5 " .
_________________________________________________________
  The quadratic function takes the form of:
_________________________________________________________
  " f(x) =  ax</span>²  + bx + c " .
_________________________________________________________
Answer choice:  [C]:  " c(x) = –8x² + 3x – 5 "  ;

  is the only answer choice provided that takes that form of the quadratic function:

  " f(x) =  ax²  + bx + c " :

in which:  " a = -8 " ; " b = 3 " ;  " c = -5 " .
____________________________________________________
You might be interested in
What is a solution to the system of equations that includes quadratic function f(x) and linear function g(x)? f(x) = 2x2 + x + 4
olga_2 [115]

The solution to the system of equations that includes quadratic function f(x) and linear function g(x) is

(\sqrt{2},\sqrt{-2}  ) and ((7+\sqrt{2)} ,(7+\sqrt{-2}))

We have given that,

f(x) = 2x^2 + x + 4

x                          g(x)      

-2                               1      

  -1                              3        

  0                              5      

  1                              7

  2                              9

<h3>What is a polynomial function?</h3>

A polynomial function is a relation where a dependent variable is equal to a  polynomial expression.

A polynomial expression is an expression including numbers and variables, where variables are raised to non-negative powers.

The general form of a polynomial expression is:

a₀ + a₁x + a₂x² + a₃x³ + ... + anxⁿ.

The highest power to a variable is the degree of the polynomial expression. When degree = 2, the function is a quadratic function.

When degree = 1, the function is a linear function.

<h3>How do we solve the given question?</h3>

The quadratic function is given to us:f(x) = 2x^2 + x + 4.

We need to determine the linear equation g(x).

Since it's a linear equation we use the two-point method to determine the equation.

<h3>What is the two-point?</h3>

y-y₁ = ((y₂-y₁)/(x₂-x₁))*(x-x₁)

We take the points g(-2) =1, g(-1) = 3

g(x) - g(1) = ((g(-2)-g(-1))/(-2+1))*(x-1)or,

g(x) - 1 = ((-2-(-1))/(-2+1))*(x-1)or, g(x) - 1 = -1(-x+1)or,

g(x) = x - 1 + 1 = x

∴ g(x) = x , is the linear function g(x)

We are asked to find the solution to the system of equations f(x) and g(x).To find the solution we need to check what is the common solution to both f(x) and g(x).

For that, we equate f(x) and g(x).2x^2 + x + 4 = x or, 2x² - x +x- 4 = 0or, 2x^2  - 4 = 02(x^2-2)=0x^2-2=0x^2-\sqrt{2}=0(x-\sqrt{2}) (x+\sqrt{2})=0(x-\sqrt{2})=0 \\x=\sqrt{2}  or x=-\sqrt{2}g(-1) = 3(from the table)g(\sqrt{2})=\sqrt{2}  \ and \ g(\sqrt{-2}) =-\sqrt{2}f(\sqrt{2}) = 2(\sqrt{2} )^2 + (\sqrt{2} ) + 3\\=2(2)+\sqrt{2} +3\\=7+\sqrt{2}g(-\sqrt{2} )= 2(\sqrt{-2} )^2 + (\sqrt{-2} ) + 3\\=2(2)+\sqrt{-2} +3\\=7+\sqrt{-2}

The solution to the system of equations that includes quadratic function f(x) and linear function g(x) is (\sqrt{2},\sqrt{-2}  ) and ((7+\sqrt{2)} ,(7+\sqrt{-2}))

Learn more about linear and  quadratic equations at

brainly.com/question/14075672

#SPJ1

5 0
2 years ago
What is the area of rhombus ABCD? Enter your answer in the box. Do not round at any steps.
Mrac [35]

Answer:

Area of the rhombus ABCD = 16 square units

Step-by-step explanation:

Area of a rhombus = \frac{1}{2}(\text{Diagonal 1})(\text{Diagonal 2})

From the graph attached,

Diagonal 1 = Distance between the points A and C

Diagonal 2 = Distance between the points B and D

Length of a segment between (x₁, y₁) and (x₂, y₂) = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^2 }

Diagonal 1 (AC) = \sqrt{(4-0)^2+(-1+1)^2} = 4 units

Diagonal 2(BD) = \sqrt{(2-2)^2+(3+5)^2} = 8 units

Now area of the rhombus ABCD = \frac{1}{2}(\text{AC})(\text{BD})

                                                       = \frac{1}{2}\times 4\times 8

                                                       = 16 units²

Therefore, area of the given rhombus is 16 units².

5 0
3 years ago
Hepl me what is the answer to this math question
Luda [366]

Answer:

c

Step-by-step explanation:

6 0
3 years ago
Help please iieieieieieieieieie
VladimirAG [237]

Answer:

THE LENGTH OF SIDE=14cm

As,

Hypotenuse ²=Base²+Perpendicular ²

H²=13²+5²

H²=169+25

H²=196

H=14

6 0
3 years ago
1 . Alberto has 318 baseball cards and 273 basketball cards. Estimate how many sports cards Alberto has. Describe the strategy y
Galina-37 [17]
For 1. To estimate how many sports cards Alberto had, you would round each number to the nearest ten, so 318 would become 320. 273 would then become 270. You would then add those two and would get 590. So, Alberto had 590 sports cards (estimated). If you were looking for the actual answer (not estimated) , you would get 591.
6 0
3 years ago
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