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3 years ago

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Which function is a quadratic function?

1 answer:

DerKrebs [107]3 years ago

5 0

The correct answer is: [C]: " c(x) = –8x²<span> + 3x – 5 " .
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The quadratic function takes the form of:
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" f(x) = ax</span>² + bx + c " .
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Answer choice: [C]: " c(x) = –8x² + 3x – 5 " ;

is the only answer choice provided that takes that form of the quadratic function:

" f(x) = ax² + bx + c " :

in which: " a = -8 " ; " b = 3 " ; " c = -5 " .
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I dont get this can someone please help me.

lora16 [44]

$5+\dfrac x 2 \geq 10\\\\\implies \dfrac x2 \geq 10-5\\\\\implies \dfrac x2 \geq 5\\\\\implies x \geq 5 \times 2\\\\\implies x \geq 10$

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2 years ago

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Melissa is saving $25 that she earned for washing her mom’s car. She earns $10 every week for doing chores, which she also saves

Fofino [41]

Answer:idk

Step-by-step explanation:

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3 years ago

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Jkl is an equilateral triangle jk= 13x+5,KL= 17X-19 AND JL= 8X+35

stira [4]

Answer:

x = 6

Step-by-step explanation:

Since the triangle is equilateral then sides are congruent.

Equate any 2 sides and solve for x

13x + 5 = 8x + 35 ( subtract 8x from both sides )

5x + 5 = 35 ( subtract 5 from both sides )

5x = 30 ( divide both sides by 5 )

x = 6

JK = (13 × 6) + 5 = 78 + 5 = 83

KL = (17 × 6) - 19 = 102 - 19 = 83

JL = (8 × 6) + 35 = 48 + 35 = 83

ΔJKL is equilateral with side = 83

4 0

3 years ago

BRAINLIEST!!! Can someone tell me how to graph inequalities?

3241004551 [841]

Answer:

whichever way the opening of the sign points go the opposite. if it is less than or equal to, closed circle

Step-by-step explanation:

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8 0

3 years ago

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Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 450 newtons stretches a sprin

vlada-n [284]

Answer:

The work done is 202.50Nm

Step-by-step explanation:

Given

$F =450N$

$x_1 = 30cm$

$x_2 = 60cm$

Required

The work done

First, we calculate the spring constant (k)

$F = kx_1$

$450N = k *30cm$

$k = \frac{450N}{30cm}$

$k =15N/cm$

So:

$F = kx_1$

$F(x) = 15x$

The work done using Hooke's law is:

$W =\int\limits^a_b {F(x)} \, dx$

This gives:

$W =\int\limits^{60}_{30} {15x} \, dx$

Rewrite as:

$W =15\int\limits^{60}_{30} {x} \, dx$

Integrate

$W =15 \frac{x^2}{2}|\limits^{60}_{30}$

This gives:

$W =15 *\frac{60^2 - 30^2}{2}$

$W =15 *\frac{2700}{2}$

$W =15 *1350$

$W =20250N-cm$

Convert to Nm

$W =\frac{20250Nm}{100}$

$W =202.50Nm$

7 0

3 years ago