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2 years ago

A 26' long painting is how many yards long

Mathematics

1 answer:

yaroslaw [1]2 years ago

6 0

Three feet is 1 yard. 26 feet would be 26/3=8 2/3 yards long.

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Angle measure represented by 36.7 rotations counterclockwise

zhannawk [14.2K]

Answer:

13,212° or 73.4π radians

Step-by-step explanation:

Each rotation is 360° or 2π radians. So, 36.7 rotations is ...

36.7×360° = 13,212°

36.7×2π = 73.4π radians

7 0

3 years ago

Chose the triangle that seems congruent to the given one

Tems11 [23]

I think the answer is: ACD

4 0

2 years ago

Read 2 more answers

The graph shows gasoline prices over time. Tell a story about how gas<br> prices change over time.

DochEvi [55]

I'm not sure if this is what you meant, but it was fun to write XD

The market was fairly stable with no problems in the economy and no big political events happening. Then the days started getting colder and people started staying in more- meaning the demand for gas dropped. This eventually it stopped decreasing and stayed like this for a bit until a hurricane is spotted and weather people say it is likely to hit the coast where this gas chart is being charted. The gas prices start increasing, at first its slow as the hurricane gets closer- and it just keeps increasing as people become more and more sure it is going to hit them and they want to evacuate.

7 0

2 years ago

Kim rolls a dice and flips a coin

tankabanditka [31]

Answer:

part a

The probability of getting a 2 is 1/6 and the probability of getting a head is 1/2. The probability of getting both is thus 1/6 x 1/2= 1/12

part b

The probability of getting an even number is 3/6 = 1/2. The probability of getting a tail is 1/2. The probability of getting both is thus 1/2 x 1/2= 1/4.

6 0

3 years ago

A fair coin is tossed three times and the events A, B, and C are defined as follows: A:{ At least one head is observed } B:{ At

kicyunya [14]

Answer:

(a) 1/2

(b) 1/2

(c) 1/8

Step-by-step explanation:

Since, when a fair coin is tossed three times,

The the total number of possible outcomes

n(S) = 2 × 2 × 2

= 8 { HHH, HHT, HTH, THH, HTT, THT, TTH, TTT },

Here, B : { At least two heads are observed } ,

⇒ B = {HHH, HHT, HTH, THH},

⇒ n(B) = 4,

Since,

$\text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}$

(a) So, the probability of B,

$P(B) =\frac{n(B)}{n(S)}=\frac{4}{8}=\frac{1}{2}$

(b) A : { At least one head is observed },

⇒ A = {HHH, HHT, HTH, THH, HTT, THT, TTH},

∵ A ∩ B = {HHH, HHT, HTH, THH},

n(A∩ B) = 4,

$\implies P(A\cap B) = \frac{n(A\cap B)}{n(S)} = \frac{4}{8}=\frac{1}{2}$

(c) C: { The number of heads observed is odd },

⇒ C = { HHH, HTT, THT, TTH},

∵ A ∩ B ∩ C = {HHH},

⇒ n(A ∩ B ∩ C) = 1,

$\implies P(A\cap B\cap C)=\frac{1}{8}$

7 0

2 years ago