
To find the gradient of the tangent, we must first differentiate the function.

The gradient at x = 0 is given by evaluating f'(0).

The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.
The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so

Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).

So the point (0, -1) lies on the tangent. Substituting into the tangent equation:
Answer:
A) X + Y = 12
B) 10Y + x = 10x + Y -18
B) 9Y = 9x -18 multiplying A) by -9
A) -9Y = 9x - 72 adding A and B we get
0 = 18x -90
x = 5
The number is 75
Double-Check
7 + 5 = 12
75 -57 = 18
Step-by-step explanation:
Answer:
The first blank is BAL and FGH
The second blank is AL
The third blank is CE and KI
The fourth and final blank is GH
explanation
i got a 5/5 on the symmetry edmentum test
product is multiplication:
2 * 2 = 4