Answer:
Step-by-step explanation:
The shortest distance d, of a point (a, b, c) from a plane mx + ny + tz = r is given by:
--------------------(i)
From the question,
the point is (5, 0, -6)
the plane is x + y + z = 6
Therefore,
a = 5
b = 0
c = -6
m = 1
n = 1
t = 1
r = 6
Substitute these values into equation (i) as follows;
Therefore, the shortest distance from the point to the plane is
Step-by-step explanation:
1. a² - ( b ² - 2bc + c² ) = a ² - b ² + 2bc - c²
2. 8p² - 18 q²
3. 3ab² - c²d + 3ab - b²c²
4. x² - 2x + 1
See the picture attached to better understand the problem
we know that
A quadrilateral is called Cyclic quadrilateral <span>if its all vertices lie on the circle.
</span><span>The opposite angles of a Cyclic - quadrilateral are supplementary
</span>so
∠A+∠C=180°
and
∠
B
+∠D=180°
therefore
the answer is<span>
C) The sum measure of ∠B and ∠D equals 180°</span>
Answer:
![(-\infty,\frac{25}{24}]](https://tex.z-dn.net/?f=%28-%5Cinfty%2C%5Cfrac%7B25%7D%7B24%7D%5D)
Step-by-step explanation:
Assuming 
is a variable:
![4i-4(i+2)\geq6(8i-8)\\\\4i-4i+2\geq48i-48\\\\2\geq48i-48\\\\50\geq48i\\\\\frac{50}{48}\geq i\\ \\\frac{25}{24}\geq i\\ \\i\leq\frac{25}{24}\\ \\(-\infty,\frac{25}{24}]](https://tex.z-dn.net/?f=4i-4%28i%2B2%29%5Cgeq6%288i-8%29%5C%5C%5C%5C4i-4i%2B2%5Cgeq48i-48%5C%5C%5C%5C2%5Cgeq48i-48%5C%5C%5C%5C50%5Cgeq48i%5C%5C%5C%5C%5Cfrac%7B50%7D%7B48%7D%5Cgeq%20i%5C%5C%20%5C%5C%5Cfrac%7B25%7D%7B24%7D%5Cgeq%20i%5C%5C%20%5C%5Ci%5Cleq%5Cfrac%7B25%7D%7B24%7D%5C%5C%20%5C%5C%28-%5Cinfty%2C%5Cfrac%7B25%7D%7B24%7D%5D)
Sqrt8 * sqrt98
= sqrt4* sqrt2 * sqrt49*sqrt2
= 2 sqrt2 * 7 sqrt2
= 2*7*2
= 28 Answer
