how does subtracting a positive constant, k, from an exponential function affect its horizontal asymptote?
1 answer:
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Answer:
vertex = (2, - 9 )
Step-by-step explanation:
Given a quadratic in standard form : ax² + bx + c : a ≠ 0
Then the x- coordinate of the vertex is
= -
x² - 4x - 5 ← is in standard form
with a = 1, b = - 4, thus
= -
= 2
Substitute this value into the quadratic for corresponding value of y
(2)² - 4(2) - 5 = 4 - 8 - 5 = - 9
vertex = (2, - 9 )
Answer:
The radius of circle B is 6 times greater than the radius of circle A
The area of circle B is 36 times greater than the area of circle A
Step-by-step explanation:
we have
<em>Circle A</em>
The radius of circle A is
-----> the radius is half the diameter
<em>Circle B</em>
Compare the radius of both circles
The radius of circle B is six times greater than the radius of circle A
Remember that , if two figures are similar, then the ratio of its areas is equal to the scale factor squared
All circles are similar
In this problem the scale factor is 6
so
therefore
The area of circle B is 36 times greater than the area of circle A