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Oksanka [162]
3 years ago
9

C + 9 - 3( c - 10) > 1Solve the inequalityPlease show steps

Mathematics
1 answer:
lana [24]3 years ago
3 0

c + 9 - 3(c - 10) > 1

We're going to treat this like a regular algebraic equation, thus most algebraic rules and properties apply.

First, apply distributive property.

c + 9 <u>- 3c + 30</u> > 1 (two - signs cancel out, creating a + sign.)

Combine like terms.

<u>-2c + 39</u> > 1

Subtract 39 from both sides.

-2c > <u>-38</u>

Divide both sides by -2.

<u>c < 19</u> (Because we're dividing by a negative number, the sign gets swapped.)


<h3>Your answer is c < 19.</h3>
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Answer:

y=4x-6

Step-by-step explanation:

to find the slope it's ((y1-y2)/(x1-x2) which in this case is (10-(-6))/(4-0) which is 16/4 aka 4

the y intercept is already given at point (0,-6)

so to write the equation is y intercept form: its y =4x-6

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find three examples of corporate logos. do they incorporate symmetry? if so, and what kind? your response should be 3-5 sentence
Tanzania [10]

Answer:

Symmetry is the property of an object to retain its shape even if it is turned or turned.

The three corporate logos are McDonald, Shell, Snapcaht

McDonald company logo is symmetrical and it is a reflective symmetry.

Shell logo is symmetrical and it is also reflective symmetry.

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4 years ago
The sum of three consecutive integers is 165. What are the integers?<br> The first integer is
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Answer:

x = 54

Step-by-step explanation:

Let the 3 consecutive integers be,

→ x, x + 1, x + 2

Then the equation is,

→ (x) + (x + 1) + (x + 2) = 165

The required value of x will be,

→ (x) + (x + 1) + (x + 2) = 165

→ 3x + 3 = 165

→ 3x = 165 - 3

→ x = 162/3

→ [ x = 54 ]

Hence, the first integer is 54.

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Use the given function and the given interval to complete parts a and b. f (x )f(x)equals=negative 2 x cubed plus 21 x squared m
Leya [2.2K]

Answer:

(A)The absolute maximum of f(x) is at x=5

Step-by-step explanation:

F(x)=−2x³+21x²−60x on [1,6]

Find the first derivative.

f'(x)=-6x²+42x-60

Set the first derivative equal to zero.

-6x²+42x-60=0

Solve to find the critical points.

x=2,5

Next, we use the endpoints and all critical points on the interval to test for any absolute extrema over the given interval.

x=1,2,5,6

This is done by evaluating the function at x=1,2,5,6.

F(1)=−2(1)³+21(1)²−60(1)=-41

F(2)=−2(2)³+21(2)²−60(2)=-52

F(5)=−2(5)³+21(5)²−60(5)=-25

F(6)=−2(6)³+21(6)²−60(6)=-36

The maximum will occur at the highest f(x) value and the minimum will occur at the lowest f(x) value.

Absolute Maximum: (5,-25)

Absolute Minimum: (2,-52)

The graph is attached.

The absolute minimum and maximum of f(x) are (2,-52) and (5,-25) respectively.

3 0
4 years ago
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