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2 years ago

I need help on these two questions

Mathematics

2 answers:

Korvikt [17]2 years ago

6 0

A: 5-3=2

B:4-3=1

these are the answers hope this helped thanks!

alisha [4.7K]2 years ago

4 0

Answer:

A) The answer is a to the second power

B) The answer is c to the first power or you can just write c

Step-by-step explanation:

If there are exponents that have the same base and you are dividing, you will need to subtract the exponents.

A)5-3=2

The answer is a to the second power

B) 4-3=1

The answer is c to the first power or you can just write c

Hope this helps!

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Please help with #1 and explain your answers! Thank you

sashaice [31]

1a) False. A square is never a trapezoid. A trapezoid has only one pair of parallel sides while the other set of opposite sides are not parallel. Contrast this with a square which has 2 pairs of parallel opposite sides.

1b) False. A rhombus is only a rectangle when the figure is also a square. A square is essentially a rhombus and a rectangle at the same time. If you had a Venn Diagram, then the circle region "rectangle" and the circle region "rhombus" overlap to form the region for "square". If the statement said "sometimes" instead of "always", then the statement would be true.

1c) False. Any rhombus is a parallelogram. This can be proven by dividing up the rhombus into triangles, and then proving the triangles to be congruent (using SSS), then you use CPCTC to show that the alternate interior angles are congruent. Finally, this would lead to the pairs of opposite sides being parallel through the converse of the alternate interior angle theorem. Changing the "never" to "always" will make the original statement to be true. Keep in mind that not all parallelograms are a rhombus.

8 0

2 years ago

Read 2 more answers

The ratio of boys to girls in a school is 5:4. if there are 500 girls , how many boys are there in the school?

lana [24]

Answer:

The number of boys in the school is;

$625$

Explanation:

Given that the ratio of boys to girls in a school is 5:4;

$5\colon4$

And there are 500 girls in the school.

The number of boys in the school will be;

$\begin{gathered} \frac{B}{G}=\frac{5}{4} \\ G=500 \\ B=\frac{5\times G}{4}=\frac{5\times500}{4} \\ B=625 \end{gathered}$

Therefore, the number of boys in the school is;

$625$

3 0

9 months ago

Consider these three numbers expressed in scientific notation 2.4 x10^4 , 6.3 x10^5 , and 9.6 x10^7

____ [38]

I considered them, but if you wanted them evaluated, here you go
24,000
630,000
96,000,000

8 0

2 years ago

PLS ANSWER QUICK THANK YOU

insens350 [35]

B!!!!!!

Step-by-step explanation:

$5 \times {10}^{4} \times 9.46\times {10}^{12} = {4.73} \times {10}^{17}$

I hope this helps, have a good day!

6 0

2 years ago

Read 2 more answers

2. Find the general relation of the equation cos3A+cos5A=0

mars1129 [50]

<h2>Answer:</h2>

$A=\frac{\pi}{8}+\frac{n\pi}{4}or\ A=\frac{\pi}{2}+n\pi$

<h2>Step-by-step explanation:</h2>

<h3>Find angles</h3>

$cos3A+cos5A=0$

________________________________________________________

<h3>Transform the expression using the sum-to-product formula</h3>

$2cos(\frac{3A+5A}{2})cos(\frac{3A-5A}{2})=0$

________________________________________________________

<h3>Combine like terms</h3>

$2cos(\frac{8A}{2})cos(\frac{3A-5A}{2})=0\\\\ 2cos(\frac{8A}{2})cos(\frac{-2A}{2})=0$

________________________________________________________

<h3>Divide both sides of the equation by the coefficient of variable</h3>

$cos(\frac{8A}{2})cos(\frac{-2A}{2})=0$

________________________________________________________

<h3>Apply zero product property that at least one factor is zero</h3>

$cos(\frac{8A}{2})=0\ or\ cos(\frac{-2A}{2})=0$

________________________________________________________

<h3>Cross out the common factor</h3>

$cos\ 4A=0$

________________________________________________________

<h3>Solve the trigonometric equation to find a particular solution</h3>

$4A=\frac{\pi}{2}or\ 4A=\frac{3\pi}{2}$

________________________________________________________

<h3>Solve the trigonometric equation to find a general solution</h3>

$4A=\frac{\pi}{2}+2n\pi \ or\\ \\ 4A=\frac{3 \pi}{2}+2n \pi\\ \\A=\frac{\pi}{8}+\frac{n \pi}{4\\}$

________________________________________________________

<h3>Reduce the fraction</h3>

$cos(-A)=0$

________________________________________________________

<h3>Simplify the expression using the symmetry of trigonometric function</h3>

$cosA=0$

________________________________________________________

<h3>Solve the trigonometric equation to find a particular solution</h3>

$A=\frac{\pi }{2}\ or\ A=\frac{3 \pi}{2}$

________________________________________________________

<h3>Solve the trigonometric equation to find a general solution</h3>

$A=\frac{\pi}{2}+2n\pi\ or\ A=\frac{3\pi}{2}+2n\pi,n\in\ Z$

________________________________________________________

<h3>Find the union of solution sets</h3>

$A=\frac{\pi}{2}+n\pi$

________________________________________________________

<h3>Find the union of solution sets</h3>

$A=\frac{\pi}{8}+\frac{n\pi}{4}\ or\ A=\frac{\pi}{2}+n\pi ,n\in Z$

<em>I hope this helps you</em>

5 0

2 years ago