Find three consecutive odd integers whose sum is 13 more than twice the largest of the three intergers

1 answer:

4 0

15,17,19
Suppose the three odd integers are #n#, #n+2# and #n+4#
Their sum is:
#n + (n+2) + (n+4) = 3n+6#
#13# more than twice the largest of the three is:
#2(n+4)+13 = 2n+21#
From what we are told these two are equal:
#3n+6 = 2n+21#
Subtract #2n+6# from both sides to get:
#n = 15#
So the three integers are:
#15, 17, 19#

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