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Veseljchak [2.6K]
3 years ago
6

NEED THE HELP ASAP!! 35 POINTS !!

Mathematics
1 answer:
Rashid [163]3 years ago
3 0

Answer:

Option B is correct friend

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Solve the system of equations (1 point)<br> y = 2x(squared) – 3<br> y = 3x - 1
alex41 [277]

\huge\fcolorbox{blue}{aqua}{Answer:}

════════════════════

1.

y =   {2x}^{2}   - 3

{2x}^{2}  - 3 = y

{2x}^{2}  = y  + 3

\frac{2x^{2}} {2}  =  \frac{y + 3}{2}

{x}^{2}  =  \frac{y + 3}{2}

x =  \sqrt \frac{2y + 6}{2}

───────────────────

2.

y = 3x - 1

3x - 1 = y

3x = y + 1

\frac{3x}{3} =  \frac{y+1}{3}

x =  \frac{y + 1}{3}

═══════════════════

Explanation:

#Carry on learning

7 0
2 years ago
1. What is the volume of the following cone? *<br> 2.5 mm<br> 1<br> 12.6 mm<br> 1
mafiozo [28]

Answer: V=πr2h 3

=π·2.52·12.6 3

=82.46681

Step-by-step explanation:

3 0
3 years ago
An arc that lies between two lines, Rays, or Segments is called
Jet001 [13]

Answer:

intercepted arc

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Christopher walks 5km south then walks on a bearing of 036º until he is due east of his starting point. How far is he from his s
harina [27]

Christopher's distance from his starting point is 3.6 km

Since Christopher initially walks South 5 km and then walks on a bearing of of 036º until he is due east of his starting point, His distance South, his distance from his starting point and his distance from his 036º bearing, all form a right-angled triangle with opposite side to the angle 036º, as his distance from his starting point, x and the adjacent side to the angle 036º, as his distance 5 km south.

Since we have both the opposite and adjacent sides of a right-angled triangle,

From trigonometric ratios,

tanФ = opposite/adjacent

tanФ = x/5 km

Now Ф = 036º

So, tan36º = x/5km

x = 5 km(tan36º)

x = 5 km (0.7265)

x = 3.633 km

x ≅ 3.6 km to 1 decimal place.

So, Christopher's distance from his starting point is 3.6 km.

Learn more about bearing here:

brainly.com/question/11684993

5 0
3 years ago
(Please Hurry!) Which expression is equivalent to the following complex fraction?
galben [10]

Answer:

The expression equivalent to the given complex fraction is

\frac{-2x+5y}{3x-2y}

Step-by-step explanation:

An easy way to solve the complex fraction is to solve the numerator and denominator separately.

Numerator:

\frac{-2}{x} + \frac{5}{y}\\ = \frac{-2y + 5x}{xy}

Denominator:

\frac{3}{y} + \frac{-2}{x}\\ = \frac{3x - 2y}{xy}

Solving the complex fraction:

[\frac{-2}{x} + \frac{5}{y}] / [\frac{3}{y} + \frac{-2}{x}]\\= [\frac{-2y + 5x}{xy}] / [\frac{3x - 2y}{xy}]

=\frac{-2y + 5x}{xy} * \frac{xy}{3x - 2y}

Common terms in the numerator and denominator cancels each other(Cross multiplication) :

= \frac{-2y + 5x}{3x - 2y}

6 0
3 years ago
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