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3 years ago

NEED THE HELP ASAP!! 35 POINTS !!

Mathematics

1 answer:

Rashid [163]3 years ago

3 0

Answer:

Option B is correct friend

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dem82 [27]

A and c are true ! I hope this helps

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2 years ago

What inequality represents the solution of 0.25x+4y-4>0.75x+12 in terms of y?

matrenka [14]

Show me the choices...................

3 0

3 years ago

Need help, please explain the answer

stellarik [79]

Answer:

7 - x meters

Step-by-step explanation:

This is a difference of squares. The formula for difference of squares is

a^2-b^2 = (a-b)(a+b)

So plug the numbers we know into this formula.

Area = lw

49 - x^2 = (a-b)(7+x)

49 - x^2 = (7-x)(7+x)

<u>The length is 7 - x meters.</u>

7 0

3 years ago

Solve with cramer's rule x+2y+3z=11, 2x+y+2z=10, 3x+2y+z=9

nalin [4]

Answer:

x = 2 , y = 0 , z = 3

Step-by-step explanation:

Cramer's rule is a rule through which we can find the solution of linear equation.

we have the three linear equations as

x+2y+3z=11

2x+y+2z=10

3x+2y+z=9

AX=B

A: coefficient matrix

X= unknown vectors(x,y,z)

D = values of the linear equation (11 , 10 , 9)

now we find the determinant of the given linear equation

determinant of the matrix will be

A = $\left[\begin{array}{ccc}1&2&3\\2&1&2\\3&2&1\end{array}\right]$ = 1(1-4) - 2(2-6) + 3(4 - 3)

= 1(-3) - 2(-4) + 3(1)

= -3+8+3 = 8

also D $\neq 0$

so the determinant is Non zero we can apply Cramer's rule

we will be replacing the first column of the coefficient matrix A with the values of D

by replacing the first column we will get the value of the variable 'x'

Dx = $\left[\begin{array}{ccc}11&2&3\\10&1&2\\9&2&1\end{array}\right]$ = 11(1-4) -2(10-18) + 3(20-9) = -33+16+33 = 16

x = $\frac{Dx}{D}$ = $\frac{16}{8}$ = 2

similarly

Dy = $\left[\begin{array}{ccc}1&11&3\\2&10&2\\3&9&1\end{array}\right]$ = 1(10-18) -11(2-6) + 3(18 -30) = -8 +44 -36 = 0

y = $\frac{Dy}{D}$ = 0

Dz= $\left[\begin{array}{ccc}1&2&11\\2&1&10\\3&2&9\end{array}\right]$ = 1(9 - 20) -2(18 - 30) + 11(4 -3) = -11 +24 +11 = 24

z = $\frac{Dz}{D}$ = $\frac{24}{8} = 3$

so we have the solution as

x = 2 , y = 0 , z = 3

Therefore the solution for the given linear equations is (2,0,3).

3 0

3 years ago

Which step was the first error made? -3\left(2x-3\right)=33−3(2x−3)=33 -6x+6=33−6x+6=33 step 1 -6x=27−6x=27 step 2 \frac{\left(-

Afina-wow [57]

Given:

The equation is

$-3(2x-3)=33$

The incorrect solution steps are given.

To find:

The first error.

Solution:

We have,

$-3(2x-3)=33$

Using distributive property, we get

$-3(2x)-3(-3)=33$

$-6x+9=33$

The given step 1 is $-6x+6=33$ , which is not correct.

Therefore, there is first error in step 1 because the distribution property is not used properly.

Hence, the correct option is D.

6 0

3 years ago