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ArbitrLikvidat [17]
3 years ago
15

3n − 2 = 7 whats the answer to n?

Mathematics
2 answers:
Svetllana [295]3 years ago
8 0

Answer:

n=3

Step-by-step explanation:

3n − 2 = 7

add 2 to each side

3n-2+2 = 7+2

3n = 9

divide by 3

3n/3 = 9/3

n = 3

tigry1 [53]3 years ago
7 0

Answer:

N=3

Step-by-step explanation:

Because when a variable and a number are together with no spaces that means that it is multiplication which means that it is 3x3 - 2 =7

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Step-by-step explanation:

1. Dividends

2. Capital gains

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where Div 1 = expected dividend paid at year's end

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3 years ago
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How to find the point-slope form for the slope of 6 and passing through(-7,1)​
MariettaO [177]

Answer: y-1=6(x+7)

Step-by-step explanation:

The formula for point-slope form is y-y_1=m(x-x_1). Since we are given the point and slope, we can directly plug them in.

y-1=6(x-(-7))            [distribute by -1]

y-1=6(x+7)

Now, we know that the point-slope form is y-1=6(x+7).

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3 years ago
To prove a<br> triangle is isosceles without the measures of each side , you need to know the?
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Two sides are congruent

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How is an inequality different from an equation? Give a real-world scenario in which you would write an inequality rather than a
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3 years ago
Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2
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For this case, we must indicate which of the given functions is not defined forx = 0

By definition, we know that:

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Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

y = \sqrt {x-2} is not defined, the term inside the root is negative when x = 0.

While y = \sqrt {x + 2} if it is defined for x = 0.

f(x)=\sqrt[3]{x}, your domain is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.

So, we have:

y = \sqrt [3] {x-2} with x = 0: y = \sqrt [3] {- 2} is defined.

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Answer:

y = \sqrt {x-2}

Option b


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4 years ago
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