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Semenov [28]
2 years ago
9

How to find the point-slope form for the slope of 6 and passing through(-7,1)​

Mathematics
1 answer:
MariettaO [177]2 years ago
8 0

Answer: y-1=6(x+7)

Step-by-step explanation:

The formula for point-slope form is y-y_1=m(x-x_1). Since we are given the point and slope, we can directly plug them in.

y-1=6(x-(-7))            [distribute by -1]

y-1=6(x+7)

Now, we know that the point-slope form is y-1=6(x+7).

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2cos^2(A)=3sin(A)\implies 2[1-sin^2(A)]=3sin(A)
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2-2sin^2(A)=3sin(A)\implies 2sin^2(A)+3sin(A)-2

\bf \\\\\\
0=[2sin(A)-1][sin(A)+2]\implies 
\begin{cases}
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now, as far as the second case....well, sine of anything is within the range of -1 or 1, so -1 < sin(A) < 1

now, we have -2 = sin(A), which simply is out of range for a valid sine, so there's no angle with such sine

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Step-by-step explanation:

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3 years ago
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Answer:

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