The problem above can be modelled as shown in the graph below
At

, the height of the water from the ground is

18-8=10
10*2.2=22
his dog is 22 lbs above the typical weight
No solutions you cancel out the ax’s
The Lagrangian for this function and the given constraints is

which has partial derivatives (set equal to 0) satisfying

This is a fairly standard linear system. Solving yields Lagrange multipliers of

and

, and at the same time we find only one critical point at

.
Check the Hessian for

, given by


is positive definite, since

for any vector

, which means

attains a minimum value of

at

. There is no maximum over the given constraints.
Alpha Printing: 400 / 60 =6.6...
Omega Printing: 1,000 / 60 = 16.6...
16.6
- 6.6
————-
10