Answer: Width = 24 inches
Step-by-step explanation:
Let W represent the width of the rectangular sign.
The length of a rectangular sign is 6 inches more than half its width. It means that the length of the rectangular sign would be
W/2 + 6
The formula for determining the area of a rectangle is expressed as
Area = length × width
The area of the sign is 432 square inches. Therefore, the equation for the area of this sign would be
W(W/2 + 6) = 432
W²/2 + 6W = 432
Multiplying both sides of the equation by 2, it becomes
W² + 12W = 864
W² + 12W - 864 = 0
W² + 36W - 24W - 864 = 0
W(W + 36) - 24(W + 36) = 0
W - 24 = 0 or W + 36 = 0
W = 24 or W = - 36
Since W cannot be negative, then
W = 24
Answer:
408.2sq inches
Step-by-step explanation:
Area of the cylindrical box = 2πr(r+h)
r is the radius = diameter/2
r = 10/2 = 5in
h is the height = 8in
Substitute
Area of the cylindrical box = 2(3.14)(5)(5+8)
Area of the cylindrical box = 2 * 3.14 * 5 * 13
Area of the cylindrical box = 408.2sq inches
The answer is: 70 .
___________________________________________
Explanation:
_________________________________
(20/100) x = 14; solve for "x".
(20/100) = 2/10 = 1/5 ;
(1/5) x = 14
x/5 = 14 ;
x = 14 * 5 ;
x = 70 . The answer is: 70 .
___________________________________
If <em>x</em> = -1, you have
2(-1) + 3 cos(-1) + <em>e</em> ⁻¹ ≈ -0.0112136 < 0
and if <em>x</em> = 0, you have
2(0) + 3 cos(0) + <em>e</em> ⁰ = 4 > 0
The function <em>f(x)</em> = 2<em>x</em> + 3 cos(<em>x</em>) + <em>eˣ</em> is continuous over the real numbers, so the intermediate value theorem applies, and it says that there is some -1 < <em>c</em> < 0 such that <em>f(c)</em> = 0.
Answer:
98
Step-by-step explanation:
Add them all up. 60+20= 80+18 = 98.
