Answer: 
We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.
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Explanation:
It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.
I'm going to use these three log rules, which apply to any base.
- log(A) + log(B) = log(A*B)
- log(A) - log(B) = log(A/B)
- B*log(A) = log(A^B)
From there, we can then say the following:
Hi there
3(p + q) = q
Solve for P
Use the distributive property
(3)(p) + (3)(q) = q
3p + 3q = q
3p = q-3q
3p = -2q
p = -2q/3
The answer is D
If you have any further questions please let me know :)
Answer:
24 = questions on test
Step-by-step explanation:
Questions answered correctly = questions on test * percent answered correctly
We know that she answered 18 correctly and that 75% were answered correctly
Substitute this information into the equation
18 = questions on test *.75
Divide by .75 on each side
18/.75 = questions on test *.75/.75
24 = questions on test
Factor out the common term; 3
(3(x + 1))^2 = 36
Use the Multiplication Distributive Property; (xy)^a = x^ay^a
3^2(x + 1)^2 = 36
Simplify 3^2 to 9
9(x + 1)^2 = 36
Divide both sides by 9
(x + 1)^2 = 36/9
Simplify 36/9 to 4
(x + 1)^2 = 4
Take the square root of both sides
x + 1 = √4
Since 2 * 2 = 4, the square root of 2 is 2
x + 1 = 2
Break down the problem into these 2 equations
x + 1 = 2
x + 1 = -2
Solve the first equation; x + 1 = 2
x = 1
Solve the second equation; x + 1 = -2
x = -3
Collect all solutions;
<u>x = 1, -3</u>
