Answer:
The numbers are -14,-13 and -12
Step-by-step explanation:
<u><em>The correct question is </em></u>
Find three consecutive integers such that the sum of the first, twice the second and three times the third is -76. What is the number?
Let
x ----> the first consecutive integer
x+1 ---> the second consecutive integer
x+2 ---> the third consecutive integer
we have that

solve for x
apply distributive property

Combine like terms

subtract 8 both sides


Divide by 6 both sides

so


therefore
The numbers are -14,-13 and -12
Answer:
v = -2
Step-by-step explanation:
-9v – 9 = -27
add 9 to each side
-9v – 9+9 = -27+9
-9v = -18
divide by -9
-9v/-9 = -18/-9
v = 2
Answer:
2 hours
Step-by-step explanation:
9.6/(60/5 x 0.4) = 2 hours
/ = divide
x = multiply
Answer:
c=144
Step-by-step explanation:
The given equation is 
If this equation has 12 and -12 as roots, then the roots must satisfy the equation.
We substitute x=12 to obtain


Solve for c to get:

This implies that:

We could have also substitute x=-12 to get the same result.