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Akimi4 [234]
3 years ago
6

What is the measure of PSQ in degrees? Angle PSR measures 99°.

Mathematics
2 answers:
11111nata11111 [884]3 years ago
8 0

we know that

Step 1

Find the value of x

m∠PSR=99°

m∠PSR=(3x+18)+(9x-27)°

so

99 =(3x+18)+(9x-27) \\ 99=12x-9\\ 12x=108\\ x=9degrees

Step 2

Find the value of m∠PSQ

m∠PSQ=(3x+18)

m∠PSQ=(3*9+18)

m∠PSQ=45°

therefore

the answer is the option

C) 45 degrees

Kisachek [45]3 years ago
4 0
The answear to the equation would be 45 degrees

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A distribution of values is normal with a mean of 220 and a standard deviation of 13. From this distribution, you are drawing sa
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Answer:

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Step-by-step explanation:

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Normal probability distribution

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In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

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Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributied random variable X, with mean \mu and standard deviation \sigma, the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 220, \sigma = 13, n = 35, s = \frac{13}{\sqrt{35}} = 2.1974

Find the interval containing the middle-most 48% of sample means:

50 - 48/2 = 26th percentile to 50 + 48/2 = 74th percentile. So

74th percentile

value of X when Z has a pvalue of 0.74. So X when Z = 0.643.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

0.643 = \frac{X - 220}{2.1974}

X - 220 = 0.643*2.1974

X = 221.41

26th percentile

Value of X when Z has a pvalue of 0.26. So X when Z = -0.643

Z = \frac{X - \mu}{s}

-0.643 = \frac{X - 220}{2.1974}

X - 220 = -0.643*2.1974

X = 218.59

The interval containing the middle-most 48% of sample means is between 218.59 to 221.41.

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