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Damm [24]
3 years ago
8

Estimate the surface area of a cube with side length 9.9 in.

Mathematics
2 answers:
vlada-n [284]3 years ago
3 0

Answer:

Estimate the surface area of a cube with side length 9.9 in.

A) 100 in²  

B) 400 in²  

C) 600 in²

D) 1000 in²

Step-by-step explanation:

9.9 to the nearest whole number is 10

We know the side length of the cube is 10

We work out the area of face and multiply by 6.

10 x 10 = 100

100 x 6 = 600 in²

kenny6666 [7]3 years ago
3 0

Answer:

600 is the answer

Step-by-step explanation:

We can round each side length to 10 in. Therefore, the area of one face is 100 in2. Since there are 6 congruent faces in a cube, the total estimated surface area of 600 in2.

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Hitman42 [59]
The absolute value of a number is its distance from 0. An easy way to think about this is that the absolute value turns a negative number positive, and has no effect on positive numbers. In this case, we are taking the absolute value of a negative number. This means we should simply make the number positive. Therefore, the answer is \frac{1}{3}
5 0
3 years ago
Find the area of this figure. use 3.14 for pi.​
Ganezh [65]
The square would be 100.
The semicircle you will use the formula πr^2/2.
That would mean you would take the 3.14x5^2/2.
(3.14x5x5)/2
(3.14x25)/2
78.5/2
=39.25
So the total area would be 139.25
7 0
3 years ago
The equation x= -7y^2 describes a parabola. Which way does the parabola open?
Nutka1998 [239]

Answer:

Downwards

Step-by-step explanation:

8 0
2 years ago
how many cubic blocks of side length 1/6 inch would take to fill a rectangular prism with a length, width, and height of 1/3 inc
borishaifa [10]
Volume of one cubic block = (1/6)^3  = 1/216 cu ins

Volume of the prism = 1/3 * 2/3 * 2/3  = 4/27  cu ins

Number of blocks to fill prism  = 4/27 / 1/216   = (216*4) / 27  =  32
3 0
3 years ago
Read 2 more answers
Help!!!!! Not the top one by the way..!
OverLord2011 [107]

Answer:

\large\boxed{x=-3\ and\ y=-11\to(-3,\ -11)}

Step-by-step explanation:

\underline{+\left\{\begin{array}{ccc}-6x+y=7\\3x-y=2\end{array}\right}\qquad\text{add both sides of the equations}\\\\.\qquad-3x=9\qquad\text{divide both sides by (-3)}\\.\qquad\boxed{x=-3}\\\\\text{Put the value of x to the first equation:}\\\\-6(-3)+y=7\\18+y=7\qquad\text{subtract 18 from both sides}\\\boxed{y=-11}

3 0
3 years ago
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