

Answer:
A) the y-intercept of g(x) is less than the y-intercept of f(x).
C is the best option and compare it with the equation of circle to get values
To find m<3, we can use the angle sum of triangles, in which the addition all angles in a triangle must be equal to 180°.
In this case:
m<3 +52°+29° = 180°
m<3 + 81° = 180°
m<3 = 180°-81°
m<3 = 99°
To find m<4, we can use adjacent angles on a straight line, where the addition of angles on a straight line must be 180°.
In this case:
m<4 + 99° = 180°
m<4 = 180°-99°
m<4 = 81°
Therefore m<3 is 99° while m<4 is 81°.
Hope it helps!
Answer:
Subtract 80 from 83 . The result of division of 8310 is 8 with a remainder of 3 .
Answer:
(a) The probability that a randomly selected alumnus would say their experience surpassed expectations is 0.05.
(b) The probability that a randomly selected alumnus would say their experience met or surpassed expectations is 0.67.
Step-by-step explanation:
Let's denote the events as follows:
<em>A</em> = Fell short of expectations
<em>B</em> = Met expectations
<em>C</em> = Surpassed expectations
<em>N</em> = no response
<u>Given:</u>
P (N) = 0.04
P (A) = 0.26
P (B) = 0.65
(a)
Compute the probability that a randomly selected alumnus would say their experience surpassed expectations as follows:
![P(C) = 1 - [P(A) + P(B) + P(N)]\\= 1 - [0.26 + 0.65 + 0.04]\\= 1 - 0.95\\= 0.05](https://tex.z-dn.net/?f=P%28C%29%20%3D%201%20-%20%5BP%28A%29%20%2B%20P%28B%29%20%2B%20P%28N%29%5D%5C%5C%3D%201%20-%20%5B0.26%20%2B%200.65%20%2B%200.04%5D%5C%5C%3D%201%20-%200.95%5C%5C%3D%200.05)
Thus, the probability that a randomly selected alumnus would say their experience surpassed expectations is 0.05.
(b)
The response of all individuals are independent.
Compute the probability that a randomly selected alumnus would say their experience met or surpassed expectations as follows:

Thus, the probability that a randomly selected alumnus would say their experience met or surpassed expectations is 0.67.