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zheka24 [161]
3 years ago
8

at a basketball game at team made 55 successful shots they were a combination of one and two point shots the team scored 92 poin

ts in all right and solve a system of equations to find out the number of each type of shot
Mathematics
1 answer:
abruzzese [7]3 years ago
8 0

Answer:

There were 18 one point shots and 37 two point shots.

Step-by-step explanation:

Let the number of one point shots be x and the number of two point shots be y .

So we have the system:

x + y = 55

x + 2y = 92

Subtract the first equation from the second, we get:

0 + y = 92 - 55 = 37.  

y = 37.

From equation 1 we have x = 55 - y

therefore x = 55 - 37 = 18.

You might be interested in
8(x + 30) + 5<br> A <br> x + 35<br> B <br> 8x + 35<br> C <br> 8x + 240<br> D <br> 8x + 245
Anon25 [30]

Answer:

D

Step-by-step explanation:

First, remove parenthesis:

8(x + 30) = 8*x + 8*30 = 8x + 240

Then, add the 5 at the end:

8x + 240 + 5 = 8x + 245

6 0
3 years ago
Read 2 more answers
Students in a statistics class are conducting a survey to estimate the mean number of units students at their college are enroll
Papessa [141]

Answer:

The 95% confidence interval for the average number of units that students in their college are enrolled in is between 11.7 and 12.5 units.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 45 - 1 = 44

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 44 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2\frac{1.5}{\sqrt{45}} = 0.4

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 12.1 - 0.4 = 11.7 units

The upper end of the interval is the sample mean added to M. So it is 12.1 + 0.4 = 12.5 units

The 95% confidence interval for the average number of units that students in their college are enrolled in is between 11.7 and 12.5 units.

8 0
3 years ago
Taking a test!!! I need help on it pleaseee!!!
ivann1987 [24]

Answer:

The first one is right the rest of them is not right correct

Step-by-step explanation:

8 0
3 years ago
-0.5 - 3.5= can someone please help me!!
romanna [79]

Answer: -4

Step-by-step explanation:

8 0
3 years ago
Please I need help ASAP!!!
lesantik [10]

Answer:

First answer.

Step-by-step explanation:

This is called the Arc length, here is the formula:

Arc length = (angle/360)*(2Pi*radius)

So,

(45/360)*(2*3.14*4)

= 3.14

SO Pi !!!!!

4 0
3 years ago
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