Which state had a population of eight hundred four thousand one hundred ninety-four

In order to find the distance between the two points we utilize the Pythagorean Theorem,: 
Distance = Square Root ( (X difference)^2 + (Y difference)^2 )
So we have
Square Root (-5 -3)^2 + (-2 -13)^2 =
Square Root -8^2 + -15^2 =
Square Root (64 + 225)
=17

Source:
http://www.1728.org/distance.htm

8 0

4 years ago

Suppose M is the midpoint of Segment AB, P is the midpoint of Segment AM, and Q is the midpoint of segment PM.

DerKrebs [107]

The coordinates of M, P and Q in terms of a and b are $M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b$ , $P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b$ and $Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b$ , respectively.

In this question we are going to use definitions of vectors and product of a vector by a scalar. Based on the information given on statement, we have the following vectorial formulas:

Location of M

$\overrightarrow{AM} = \frac{1}{2}\cdot \overrightarrow{AB}$

$\vec M - \vec A = \frac{1}{2}\cdot \vec B - \frac{1}{2}\cdot \vec A$

$\vec M = \frac{1}{2}\cdot \vec A +\frac{1}{2}\cdot \vec B$

$M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b$

Location of P

$\overrightarrow{AP} = \frac{1}{2}\cdot \overrightarrow{AM}$

$\vec P - \vec A = \frac{1}{2}\cdot \vec M - \frac{1}{2}\cdot \vec A$

$\vec P = \frac{1}{2}\cdot \vec A +\frac{1}{2}\cdot \vec M$

$\vec P = \frac{3}{4}\cdot \vec A + \frac{1}{4}\cdot \vec B$

$P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b$

Location of Q

$\overrightarrow{QM} = \frac{1}{2}\cdot \overrightarrow{PM}$

$\vec M - \vec Q = \frac{1}{2}\cdot \vec M - \frac{1}{2}\cdot \vec P$

$\vec Q = \frac{1}{2}\cdot \vec P - \frac{1}{2}\cdot \vec M$

$\vec Q = \frac{1}{2}\cdot \left(\frac{3}{4}\cdot \vec A + \frac{1}{4}\cdot \vec B\right) -\frac{1}{2}\cdot \left(\frac{1}{2}\cdot \vec A + \frac{1}{2}\cdot \vec B\right)$

$\vec Q = \frac{1}{8}\cdot \vec A -\frac{1}{8}\cdot \vec B$

$Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b$

The coordinates of M, P and Q in terms of a and b are $M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b$ , $P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b$ and $Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b$ , respectively.

We kindly invite to check this question on midpoints: brainly.com/question/4747771

4 0

2 years ago

Question on picture attached, easy but i’m stuck (need help asap)

Ludmilka [50]

Answer:

∠CDF = 54

Step-by-step explanation:

In ΔAEB,

AE ≅ AB

∠ABE = ∠E = x {Angles opposite to equal sides are equal}

∠EAB + ∠E +∠ABE = 180 {angle sum property of triangle}

26 + x + x = 180

26 + 2x = 180

2x = 180 - 26

2x = 154

x = 154/2

x = 77

∠ABE = ∠E = 77

In quadrilateral AECF

∠A + ∠E + ∠C + ∠F = 360

90 + 77 + ∠C + 90 = 360

∠C + 257 = 360

∠C = 360 - 257

∠C = 103

∠FCD + ∠BCD = ∠C

∠FCD + 67 = 103

∠FCD = 103 - 67

∠FCD = 36

ΔFCD,

∠FCD + ∠CDF + ∠CFD = 180

36 + ∠CDF + 90 = 180

∠CDF + 126 = 180

∠CDF = 180 - 126

∠CDF = 54

7 0

3 years ago