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4 years ago

Please solve with working much appreciated

Mathematics

1 answer:

irina [24]4 years ago

6 0

Answer:

angle G = 70

Step-by-step explanation:

well since the two legths are the same that means the two cornners are going to be the exact same length.

180 - 40 = 140

140 / 2 = 70

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If x^3 times x^b equals x^15, which could be a correct value for "b?"

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B=5
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3 years ago

Given the polynomial function below, find F(-1).

mrs_skeptik [129]

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$f(x) = - {x}^{3} - {x}^{2} + 1$

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$f( - 1) = - ({ - 1})^{3} - ({ - 1})^{2} + 1 \\$

$f( - 1) = - ( - 1) - (1) + 1$

$f( - 1) = 1 - 1 + 1$

$f( - 1) = 2 - 1$

$f( - 1) = 1$

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The correct answer is (( D )) .

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3 years ago

Ella has a part-time job selling cupcakes at a cart in the park. She is paid $25 for a shift plus a fee of $0.25 for each cupcak

mojhsa [17]

9514 1404 393

Answer:

A) t = 0.25c +25

B) c = 52

C) 3 weekday shifts

Step-by-step explanation:

A. The amount Ella earns is $0.25 per cupcake, so for c cupcakes, that is ...

0.25c

In addition, she is paid $25, so her total amount she is paid is ...

t = 0.25c +25

B. In order to earn $38, the number of cupcakes sold must be ...

38 = 0.25c +25

13 = 0.25c . . . . . . subtract 25

52 = c . . . . . . . . . multiply by 4

Ella sold 52 cupcakes to earn $38.

C. On one of the average weekdays, Ella could be expected to earn ...

t = 0.25(36) +25 = 34

Then for 3 weekday shifts, her earnings would be 3($34) = $102. (It would take Ella 3 weeks to earn $300.)

On one of the average weekend shifts, Ella could be expected to earn ...

t = 0.25(62) +25 = 40.50

Then for 2 weekend shifts, her earnings would be 2($40.50) = $81. (It would take Ella 4 weekends to earn $300.)

Ella would earn $300 more quickly by working weekday shifts.

8 0

3 years ago

Rolf spent 15 hours last week practicing his saxophone. If 3/10 of the time was spent practicing warm-up routines, how much time

rusak2 [61]

Answer:

(3/10)*15= 9/2= 4.5 hours practicing warm up routines

5 0

3 years ago

If a coin is flipped 75 times, in how many ways could there be exactly two tails?

Dimas [21]

Answer:

2775 ways

Step-by-step explanation:

We have been given the case to choose exactly two tails when flipped 75 times means $^{75}C_2$

Since, $^nC_r$ is equal to $\frac{n!}{r!\cdot(n-r)!}$

Here n =75, r=2 substituting the values we will get

$\frac{75!}{2!(75-2)!}$

$n!=n\cdot (n-1)\cdot (n-2).....1$

After simplification we will get $\frac{75\cdot 74\cdot 73!}{2!\cdot73!}$

Cancel out the common term that is 73! we will get

after more simplification we will get $\frac{75\cdot 74\cdot}{2!}$

Finally, we will get $\frac{75\cdot 74\cdot}{2}=75\cdot37=2775$

4 0

3 years ago

Read 2 more answers