Answer:
true
Step-by-step explanation:
Let x represent amount invested in the higher-yielding account.
We have been given that a man puts twice as much in the lower-yielding account because it is less risky. So amount invested in the lower-yielding account would be
.
We are also told that his annual interest is $6600 dollars. We know that annual interest for one year will be principal amount times interest rate.
, where,
I = Amount of interest,
P = Principal amount,
r = Annual interest rate in decimal form,
t = Time in years.
We are told that interest rates are 6% and 10%.


Amount of interest earned from lower-yielding account:
.
Amount of interest earned from higher-yielding account:
.

Let us solve for x.



Therefore, the man invested $30,000 at 10%.
Amount invested in the lower-yielding account would be
.
Therefore, the man invested $60,000 at 6%.
The answer is:
a: 1 = 2(x^2<span> + 2</span>x<span>)
b:</span>1 = 2x^2 + 4<span>x
d:</span>3 = 2(x + 1)^2
you can tell these are your answer when you solve it.
Hope this helps!
Answer:
Option A is correct that is 
Step-by-step explanation:
We have been given a formula 

We will put values of n in
when n=2 we get
when n=3
Therefore, Option A is correct that is 
Answer:
i cant see the picture
Step-by-step explanation: