Answer:
(2) A
Step-by-step explanation: easy Math
Answer:
1. Objective function is a maximum at (16,0), Z = 4x+4y = 4(16) + 4(0) = 64
2. Objective function is at a maximum at (5,3), Z=3x+2y=3(5)+2(3)=21
Step-by-step explanation:
1. Maximize: P = 4x +4y
Subject to: 2x + y ≤ 20
x + 2y ≤ 16
x, y ≥ 0
Plot the constraints and the objective function Z, or P=4x+4y)
Push the objective function to the limit permitted by the feasible region to find the maximum.
Answer: Objective function is a maximum at (16,0),
Z = 4x+4y = 4(16) + 4(0) = 64
2. Maximize P = 3x + 2y
Subject to x + y ≤ 8
2x + y ≤ 13
x ≥ 0, y ≥ 0
Plot the constraints and the objective function Z, or P=3x+2y.
Push the objective function to the limit in the increase + direction permitted by the feasible region to find the maximum intersection.
Answer: Objective function is at a maximum at (5,3),
Z = 3x+2y = 3(5)+2(3) = 21
In general polynomial <span>is an </span>expression<span> consisting of </span>variables<span> (or </span>indeterminates<span>) and </span>coefficients<span>, that involves only the operations of </span>addition<span>, </span>subtraction<span>, </span>multiplication<span>, and non-negative </span>integer exponents<span>.
So this equation is polynomial</span>
Answer:
![=x^3-x^2-30x+72](https://tex.z-dn.net/?f=%3Dx%5E3-x%5E2-30x%2B72)
Step-by-step explanation:
Distribute parentheses:
![=xx^2+x\left(-7x\right)+x\cdot \:12+6x^2+6\left(-7x\right)+6\cdot \:12](https://tex.z-dn.net/?f=%3Dxx%5E2%2Bx%5Cleft%28-7x%5Cright%29%2Bx%5Ccdot%20%5C%3A12%2B6x%5E2%2B6%5Cleft%28-7x%5Cright%29%2B6%5Ccdot%20%5C%3A12)
Apply minus - plus rule:
![=x^2x-7xx+12x+6x^2-6\cdot \:7x+6\cdot \:12](https://tex.z-dn.net/?f=%3Dx%5E2x-7xx%2B12x%2B6x%5E2-6%5Ccdot%20%5C%3A7x%2B6%5Ccdot%20%5C%3A12)
Simplified:
![=x^3-x^2-30x+72](https://tex.z-dn.net/?f=%3Dx%5E3-x%5E2-30x%2B72)
Its complicated but..
use the domain {-4, -2, 0, 2, 4} the codomain [-4, -2, 0, 2, 4} and the range {0, 2, 4} to create a function that is niether one
lesya [120]
Answer:
See attachment
Step-by-step explanation:
We want to create a function that is neither one-to-one or on to given that:
The domain is {-4, -2, 0, 2, 4}
The codomain is [-4, -2, 0, 2, 4}
The range is {0, 2, 4}
The function in the attachment is an example of such function.
The function is not one-to-one because there are different different x-value in the domain that has the same y-value in the co-domain.
It is not an on to function because the range is not equal to the co-domain.