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3 years ago

I will give you 40 points if you answer and plz explain why that is the correct answer

Mathematics

1 answer:

alukav5142 [94]3 years ago

4 0

Can you please take a better picture please

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Find the product of (k – 9)2 using the perfect square trinomial rule shown on the left. The product (k – 9)2 can also be written

Crank

$(a-b)^2=a^2-2ab+b^2$

$(k-9)^2=k^2-2\cdot k\cdot9+9^2=k^2-18k+81$

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3 years ago

What is f(−3) for the function f(a)=−2a2−5a+4?

Readme [11.4K]

Answer:

f(-3)

f(a) = -2a² - 5a + 4

Substitute a with its value, -3

f(-3) = -2(-3²) - 5(-3) + 4

f(-3) = -2(9) + 15 + 4

f(-3) = -18 + 19

f(-3) = 1

the value of f(-3) is 1.

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3 years ago

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Prove that the value of the expression does not depend on the variable x: x4–(x2–1)(x2+1)

Reil [10]

$x^4 - (x^2-1)(x^2+1)$

Use the formula: (a+b)(a-b) = a^2 - b^2

$x^4 - [(x^2)^2 - 1^2]\\\\x^4 - (x^4-1)\\\\x^4 - x^4 + 1\\\\\boxed{\bf{1}}$

No matter what the value of 'x' is, the final answer will always be 1.

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3 years ago

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How Do is solve <br><br> y=2x-5

Murrr4er [49]

You can either graph it, or input values of x to follow the order of operations and determine values of y.

6 0

3 years ago

A publication released the results of a study of the evolution of a certain mineral in the Earth's crust. Researchers estimate

san4es73 [151]

Answer:

a) $E(A)=\frac{1+6}{2}=3.5 ppm$

b) $P(2.875$

c) $P(X$

Step-by-step explanation:

If we work with the limits defined from 5 to 10 then part b and c from this question not makes sense. If we work with the limits 1 and 6 all the parts for the question makes sense because if we work with 5 and 10 the only thing that we can find is the expected value $E(A) = \frac{5+10}{2}= 7.5$

Assuming the following correct question : "A publication released the results of a study of the evolution of a certain mineral in the Earth's crust. Researchers estimate that the trace amount of this mineral x in reservoirs follows a uniform distribution ranging between 1 and 6 parts per million"

Solution to the problem

Let A the random variable that represent " amount of the mineral x ". And we know that the distribution of A is given by:

$A\sim Uniform(1 ,6)$

Part a

For this uniform distribution the expected value is given by $E(X) =\frac{a+b}{2}$ where X is the random variable, and a,b represent the limits for the distribution. If we apply this for our case we got:

$E(A)=\frac{1+6}{2}=3.5 ppm$

Part b

For this case we can use the cumulative distribution function for the uniform distribution given by:

$F(X=x)= \frac{x-a}{b-a} = \frac{x}{6-1} =\frac{x-1}{5} , 1 \leq X \leq 6$

And we want this probability: $P(2.875$ Part c

For this case we want this probability:

$P(X$

3 0

3 years ago