The original number is 7 i think.
10(x^2) = 70x
10x^2 - 70x = 0
x^2 -7x =0
Δ= b^2 -4ac
where c doesnt exist=0
Δ= 49
-b ± √Δ /2a
7 ± √49 /2
7±7/2
x is either 14/2= 7
or 1/2, which doesnt work.
Lets see:
10(7^2) = 70•7
10•49 = 490
and that is right.
i hope my logic is correct.
If i read it right it would be 4*10^2
<em><u>Answer:</u></em>
Option 1 or 16 + h = 24
<em><u>Step-by-step explanation:</u></em>
Tyrone ate 16 hamburgers today.
Tyrone had 24 hamburgers.
Hamburger = h.
We want to find how much Tyrone had left so:
h = 24 - 16
OR (we can move 16 to the other side)
h + 16 = 24
Option 1 is the answer
Answer:
z = 4
y = -1
x = 2
Step-by-step explanation:
x - y = 3
Therefore => x = 3 + y
y + 2z =7
Therefore => y= 7 - 2z
We have the equation :
2x + 3y + 4z = 17
2(3 + y) + 3(7 - 2z) + 4z = 17
6 + 2y + 21 - 6z +4z = 17
2(7 -2z) - 2z + 27 = 17
14 - 4z - 2z + 27 = 17
-6z + 41 = 17
-6z = -24
z = 4
All I can say is 1 and 2 are correct.
