1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
igomit [66]
3 years ago
13

Find the volume of the cone. Round your answer to the nearest tenth.

Mathematics
1 answer:
Anton [14]3 years ago
6 0

Answer:115.4685yd^3

Step-by-step explanation:

Volume of cone=1/3πr2h

V=1/3×3.142×3.5yd×3.5yd×9yd

V=115.4685yd^3

You might be interested in
A box contains 2 plain pencils and 2 pens. A second box contains 7 color pencils and 3 crayons. One item from each box is chosen
photoshop1234 [79]
In the box containing the 2 plain pencils and 2 pens, there would be a 50% chance of getting a pen. In the other box containing 7 color pencils and 3 crayons there would be a 30% chance of getting a crayon.
8 0
3 years ago
12 inches to 36 inches
Schach [20]
You have to Multiply times 3...
12•3=36
36/12=3
3 0
3 years ago
Can someone please help its due soon.ill give brainliest!
leva [86]

Answer:

18 and 6

4x= 18+6

4x=24

x=24/4

x=6

4x= 6×4

24

2x+3

6×2

12+3

15

3 0
3 years ago
Osvoldo has a goal of getting at least 30% of his grams of carbohydrates each day from whole grains. Today, he ate 220 grams of
pochemuha

Answer:

Answer: Osvoldo did not meet his goal.

Step-by-step explanation:

Total carbohydrate ate by Osvoldo = 220 g

carbohydrate from grains = 55 g

Percentage of carbohydrate of grain is

\begin{gathered}=\dfrac{\text { carbohydrate taken from grains}}{\text {Total carbohydrate}} \times 100\\\\= \dfrac{55}{220} \times 100= 25 \%\end{gathered}

=

Total carbohydrate

carbohydrate taken from grains

×100

=

220

55

×100=25%

Goal of getting carbohydrate from grains = at least 30%

but he ate only 25% of carbohydrate

Hence, Osvoldo did not meet his goal as he ate less carbohydrate than his goal.

8 0
3 years ago
Which statement is true regarding the graphed functions?
Vladimir79 [104]

let's analyze each case to determine the solution

<u>case 1)</u> f(0) = 2 and g(–2) = 0

For x=0-----> find the value of f(0) in the graph-----> f(0)=4

For x=-2-----> find the value of g(-2) in the graph-----> g(-2)=0

therefore

the statement of the case 1) is false

<u>case 2)</u> f(0) = 4 and g(–2) = 4

For x=0-----> find the value of f(0) in the graph-----> f(0)=4

For x=-2-----> find the value of g(-2) in the graph-----> g(-2)=0

therefore

the statement of the case 2) is false

<u>case 3)</u> f(2) = 0 and g(–2) = 0

For x=2-----> find the value of f(2) in the graph-----> f(2)=0

For x=-2-----> find the value of g(-2) in the graph-----> g(-2)=0

therefore

the statement of the case 3) is true

<u>case 4)</u> f(–2) = 0 and g(–2) = 0

For x=-2-----> find the value of f(-2) in the graph-----> f(-2) is greater than 12

For x=-2-----> find the value of g(-2) in the graph-----> g(-2)=0

therefore

the statement of the case 4) is false

therefore

<u>the answer is</u>

f(2) = 0 and g(–2) = 0-------> this statement is true


6 0
3 years ago
Read 2 more answers
Other questions:
  • given the equations 9x + (3)/(4)y + 6 and 2x + (1)/(2)y=9 by what factor would you multiply the sencond equation to eliminate y
    11·1 answer
  • Use your calculator to find the smallest solution to <img src="https://tex.z-dn.net/?f=-5e%5E%7B-4x%2B2%7D%2B3%3D%5Cfrac%7B1%7D%
    5·1 answer
  • Find the value of y​
    6·1 answer
  • Please help me with this
    5·2 answers
  • Please help with this
    6·2 answers
  • Write the expression 5^2/3 without using exponents
    5·1 answer
  • Write <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B22%20%7D%7B4%7D%20" id="TexFormula1" title=" \frac{22 }{4} " alt=" \fra
    13·2 answers
  • Please help
    11·1 answer
  • Find the perimeter of the following figure:
    15·1 answer
  • The two interior opposite Angel's of a triangle are 60° and 80°. Find the measure of the exterior angle. ​
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!