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MA_775_DIABLO [31]
3 years ago
8

Simplify 2x^4y^5 * 3x^5y^7z^3

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
4 0
2x^4y^5(3x^5y^7z^3) = 6x^9 y^12 z³ is your answer

hope this helps

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Digiron [165]
Given:

<span>The average number of daylight hours each month in Springfield in 2015:

Jan   9.5
Feb  10.5
Mar  12
Apr  13.25
May  14.5
Jun   15
Jul    14.75
Aug   13.75
Sep    12.5
Oct    11.0
Nov   9.75
Dec   9.25

Now, we observe the trend of the monthly hours, it starts with a low value then increases and decreases back to the original value. This represents a parabola with the highest point of 15 hours. </span><span />
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4 because 12:15 is 4:5
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. Find the variance of the set of numbers 2,3,5,6,8.​
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4 0
3 years ago
today each cookie costs 0.75 less than the normal price. pight now if you buy 7 of them it will only cost you 2.80 . writw an eq
lbvjy [14]

The normal price of each cookie is $1.15 derived from the equation, c =today price of each cookie + 0.75

<u>Solution:</u>

Given, Today each cookie costs 0.75 less than the normal price.

Right now if you buy 7 of them it will only cost you 2.80

We have to write an equation to determine the normal price of each cookie(c)

And, we are given that, today 7 cookies cost 2.80

Let the cost of one cookie today be “n”

Then we get,

Today 7 cookies ⇒ 2.8

Then, 1 cookie ⇒ n  

By criss cross multiplication we get,

\begin{array}{l}{7 \times n=2.8 \times 1} \\\\ {\rightarrow 7 n=2.8} \\\\ {\rightarrow n=0.4}\end{array}

Which means that, each cookie costs $0.4 today

Now, we know that,

<em>normal price of each cookie, c = today price of each cookie + $ 0.75  </em>

c = 0.4 + 0.75

c= 1.15

Hence, the normal cost of each cookie is $1.15 derived from the equation, c = today price of each cookie + 0.75

3 0
3 years ago
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