Question

Solve the inequality x^2 - x - 12 <0

Answer 1

Answer:

X<12

Step-by-step explanation:

x² - x - 12 <0 any number without a power is to power 1.

x² - x^1 - 12<0

x^1 - 12 <0

x - 12 <0 any to the power 1 is that same number example p^1=p

x - 12 + 12<0 + 12

x<12

Answer 2

Answer:

$x( - 3and4)$

$x {}^{2} - x - 12 = 0 \\ x = \frac{ - ( - 1) + \sqrt{( - 1) {}^{2} - 4 \times 1( - 12) } }{?2} \\ x = \frac{1 + 7}{2} \\ x = 4 \\ x = - 3 \\ (x - 4)(x + 3) < 0 \\ x - 4 > 0 \\ x + 3 < 0 \\ xe0 \\ x + 3 > 0 \\ x - 4 < 0 \\ \: de \: solution \: satisfying \: both \: enquities \: is \: x( - 3and4)$