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marshall27 [118]
3 years ago
11

At a factory, two machines pack bottles into boxes for shipping. Machine A can pack 8 boxes per minute, and Machine B can pack 1

1 boxes per minute.
1. Before shipment, an inspector found that 7 of the boxes were defective and could not be shipped. At least 200 boxes were approved for shipment. Write and solve an inequality to find the amount of time Machine A spent packing the boxes that were approved for shipment.​
Mathematics
2 answers:
Komok [63]3 years ago
6 0
Answer: 25 minutes for Machine A spent packing boxes
Aleksandr-060686 [28]3 years ago
5 0

Answer: 25 minutes

Step-by-step explanation:

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What is the answer of -3 ____ -4
ruslelena [56]

Answer:

>

Step-by-step explanation:

-3 is greater than -4

3 0
3 years ago
mateo has 6.5 cups of sugar. how many batches of cookies can he make if each batch requires 3/4 cups of sugar?
Kitty [74]

Answer:

8

Step-by-step explanation:

Hope that helps

3 0
3 years ago
Read 2 more answers
Given that the circumferential of a circle is 22cm calculate its diameter​
Ipatiy [6.2K]

Answer:

diameter =7 cm

Step-by-step explanation:

circum=2pi×r

2\pi \times r

2×pi×r=22

2×22÷7×r=22

r=22×7÷44

r=7÷2

r=3.5

d=2×r=2×3.5=7

6 0
2 years ago
In the partial sequence …, 987, N, 2584, 4181, …, each new term is the sum of the two previous terms. Find the whole number valu
Alina [70]

Answer: 2584

Step-by-step explanation:

We can find N with 2584 and 4181.

4181 - 2584

= 1597

We can also check our answer by adding 1597 and 987

1597 + 987

= 2584

5 0
3 years ago
There are three boxes: one with two golden coins, one with two silver coins, and one with one golden coin and one silver coin. A
krek1111 [17]

Answer:

Step-by-step explanation:

From Bayes' theorem is stated mathematically as the following equation:[2]

{\displaystyle P(A\mid B)={\frac {P(B\mid A)\,P(A)}{P(B)}},}

where A and B are events and P(B) ≠ 0.

P(A) and P(B) are the probabilities of observing A and B without regard to each other.

P(A | B), a conditional probability, is the probability of observing event A given that B is true.

P(B | A) is the probability of observing event B given that A is true.

At this point, go through the attached file before you continue with part B.

Part B)

P(silver) = P(silver from SS)+P(silver from GS)

note P(SS)=P(GG)=P(GS) = 1/3

P(silver from SS) = 1

P(silver from GS) = 1/2

hence

P(Silver from SS) = 1/3

P(Silver from GS) = 1/3 *1/2

P(Silver) = 1/3*1+1/3*1/2

required probability = P(Silver from SS)/P(Silver) = 2/3

4 0
3 years ago
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