Raymond and Shauna must convince at least 5 more city council member. Because if every 2/6 members agree with the idea, then there would be 8 people out 24 that already agree with the idea. So if you have already 8 members then to make 13, you just need 5 (8 + 5=13) more people to 13.
The expression that is equivalent to 14xy – 28x – 36y + 48 is 2[7x(y-2)-6(3y-4)]
<h3>Factorizing expressions</h3>
Factorization is a way of separating the equations into two separate factors.
Given the expression below;
14xy – 28x – 36y + 48
Group
(14xy – 28x) – (36y + 48)
14x(y - 2) - 12(3y-4)
Factor out the value of 2 from both terms
2[7x(y-2)-6(3y-4)]
Hence the expression that is equivalent to 14xy – 28x – 36y + 48 is 2[7x(y-2)-6(3y-4)]
Learn more on factorization here: brainly.com/question/25829061
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The effect of Claudia's changing the height of of the triangle from 1 inch
to 3 inches is the option;
- The height of the triangle changed to three inches but the width remained 1 inch
<h3>Which option gives the effect of changing the height?</h3>
The given dimensions of the equilateral triangle Claudia added are;
Height of the triangle = 1 inch
Width of the triangle = 1 inch
The value Claudia typed in the Shape Height box = 3
Required:
What happened to the shape after she press Enter
Solution:
By entering 3 in the Shape Height box, changes the height of the
equilateral triangle to 3 inches but the width remains 1 inches
From a similar question posted online, the correct option is therefore;
- The height of the triangle changed to three inches but the width remained 1 inch
Learn more about triangles here:
brainly.com/question/16430835
If we use the rules we say that <span>when we multiply two numbers we get the result in the numbers the least significant number has in the multiplication. So we may proceed like this:</span>
67.6 x 1.2 = 81.12
<span>As the decimal part does not continue indefinitely we can leave the answer as it is.</span><span> if the answer was 81.123612356213 then we leave it like </span><span>81.1 as the rules say</span>
