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4 years ago

Select from the drop-down menu to correctly complete the statement about the given figures.

Mathematics

2 answers:

BigorU [14]4 years ago

6 0

The correct answer is:

Not similar

Explanation:

Similar figures have the same angle measurement and corresponding sides are proportional. The ratio for the sides AD and EH is 2:6 = 1:3; the ratio for the sides AB and EF is 4:8 = 1:2. The ratios are not the same, so the figures are not proportional and are not similar.

denpristay [2]4 years ago

3 0

not similar because it does not have the same shape or mirrior image think of translation,reflection,and rotation for example circles are similar

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What is the imagine point of (-1,-5) after a translation left 1 unit and up 4 units?

Katena32 [7]

Answer:

-2, -1

Step-by-step explanation:

So moving left would affect the x-axis.

Left would move it to the negatives so -1 - 1 = -2.

Moving up would affect the y-axis.

Up would move towards the positive so -5 + 4 = -1.

-2, -1

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3 years ago

Heeeeeeelppppppppppp

sleet_krkn [62]

Step-by-step explanation:

I'll help you darling

a. B

b. 2.6 + x = 10.4

c. x = 10.4 - 2.6

= 7.8

d. This is to say before mia added the 2.6 litres of what the pitcher contained 7.8 litres of water already

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3 years ago

PLS HELP SHOW ALL UR STEPS AND PLZ DONT GIVE ME A LINK TO FOLLOW IM JUS A LITTLE KID TRYNNA GET THIS RIGHT

madam [21]

third side =√{30²+16²)=34

sin theta/2=16/34

theta/2=sin-¹(16/34)

theta=28.07×2=56.14

7 0

3 years ago

Read 2 more answers

What is the y-intercept of the function f(x) = -2/9x + 1/3 -2/9 -1/3 1/3 2/9

sergeinik [125]

Answer:

-1/3

Step-by-step explanation:

7 0

4 years ago

You have asked to design a rectangle box with a square base and an open top. The volume of the box must be620 cm to the 3rd powe

hammer [34]

Answer:

$69.21

Step-by-step explanation:

Since the box has a square base the length and breadth of the box will be equal. Let it be $x$

Let h be the height of the box

V = Volume of the box = $620\ \text{cm}^3$

$x^2h=620\\\Rightarrow h=\dfrac{620}{x^2}$

Now surface area of the box with an open top is given

$s=x^2+4xh\\\Rightarrow s=x^2+4x\dfrac{620}{x^2}\\\Rightarrow s=x^2+\dfrac{2480}{x}$

Differentiating with respect to x we get

$\dfrac{ds}{dx}=2x-\dfrac{2480}{x^2}$

Equating with zero

$0=2x-\dfrac{2480}{x^2}\\\Rightarrow 2x^3-2480=0\\\Rightarrow x^3=\dfrac{2480}{2}\\\Rightarrow x=(1240)^{\dfrac{1}{3}}\\\Rightarrow x=10.74$

Double derivative of the function

$\dfrac{d^2s}{ds^2}=2+\dfrac{4960}{x^3}=2+\dfrac{4960}{1240}\\\Rightarrow \dfrac{d^2s}{ds^2}=6>0$

So, x at 10.74 is the minimum value of the function.

$h=\dfrac{620}{x^2}\\\Rightarrow h=\dfrac{620}{10.74^2}\\\Rightarrow h=5.37$

So, minimum length and breadth of the box is 10.74 cm while the height of the box is 5.37 cm.

The total area of the sides is $4xh=4\times 10.74\times 5.37=230.7\ \text{cm}^2$

The area of the base is $x^2=10.74^2=115.35\ \text{cm}^2$

Cost of the base is $0.40 per square cm

Cost of the side is $0.10 per square cm

Minimum cost would be

$230.7\times 0.1+0.4\times 115.34=\$69.21$

The minimum cost of the box is 69.21 dollars.

8 0

3 years ago