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3 years ago

C=85x+60 solve for x

1 answer:

3 0

To solve for x:

C=85x+60 subtract 60 from both sides

C - 60=85x+60 - 60

C - 60 = 85x now divide by 85 both sides

(C - 60)/85 = x

So we can write:
$x= \frac{C-60}{85}$

I hope that helps!

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Need help solving for X

sasho [114]

I hope this helps you 132-x+6x-12=180 5x=60 x=12 6y+18+132-x=180 6y+150-12=180 6y=42 y=7

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3 years ago

Rosa is at most 29 years old

liq [111]

Answer:

R≤29.

Step-by-step explanation:

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3 years ago

Read 2 more answers

After one round in a card game, your score was -50 points. After the second round, your score was 29 points. How many points did

Fantom [35]

Answer:

Step-by-step explanation:

$score = 29 - (-50)$

Expressed as: The score is the difference between 29 and -50.

Simplify:

$score = 29 + 50$

Result:

$score = 79$

Feel free to ask questions, and don't forget to mark as Brainliest if this helped.

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4 years ago

Jonathan is 6 feet 2 inches tall. There are 2.54 centimeters in 1 inch. What is Jonathan’s height in centimeters?

VikaD [51]

Answer:

187.96

Step-by-step explanation:

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3 years ago

4. Meagan invests $1,200 each year in an IRA for 12 years in an account that earned 5%

Nina [5.8K]

Part A)

$\bf \qquad \qquad \textit{Future Value of an ordinary annuity}\\
\left. \qquad \qquad \right.(\textit{payments at the end of the period})
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]$

$\bf \qquad 
\begin{cases}
A=
\begin{array}{llll}
\textit{accumulated amount}\\
\end{array}
\begin{array}{llll}

\end{array}\\
pymnt=\textit{periodic payments}\to &1200\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &12
\end{cases}$

$\bf A=1200\left[ \cfrac{\left( 1+\frac{0.05}{1} \right)^{1\cdot 12}-1}{\frac{0.05}{1}} \right]\implies A\approx 19100.55$

part B)

so, for the next 11 years, she didn't make any deposits on it and simple let it sit and collect interest, compounded annually at 5%.

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\ 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$19100.55\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &11
\end{cases}
\\\\\\
A=19100.55\left(1+\frac{0.05}{1}\right)^{1\cdot 11}\implies A\approx 32668.42$

part C)

well, for 12 years she deposited 1200 bucks, that means 12 * 1200, or 14,400.

now, here she is, 12+11, or 23 years later, and she's got 32,668.42 bucks?

all that came out of her pocket was 14,400, so 32,668.42 - 14,400, is how much she earned in interest.

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4 years ago