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FrozenT [24]
3 years ago
14

Please answer correctly, show all steps you did to solve this problem, and i will mark brainliest to best answer

Mathematics
1 answer:
GalinKa [24]3 years ago
6 0

Answer:

Since the values vary from 0.5 to 4.5, let's take 5 intervals of width 1 unit each

(Lower boundary is included, upper boundary is not)

Average

no. of --------> frequency

movies

_______ __________

0 - 1 --------------> 1

1 - 2 --------------> 5

2 - 3 --------------> 5

3 - 4 --------------> 2

4 - 5 --------------> 1

For frequencies, just count the data values in each interval

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Plz help me with this problem!
sergiy2304 [10]

Answer:

It's 99.00900

Step-by-step explanation:

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3 years ago
Find midpoint of xy<br> X(7,-5) and y (9,-1)
Jlenok [28]

Answer:

(8,-3)

Step-by-step explanation:

(x1+x2/2), (y1+y2/2)

7+9/2=16/2=8           x=8

-5-1/2=-6/2=-3          y=-3

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77julia77 [94]

Answer:

6x+48+15+3x and 9x+63

Step-by-step explanation:

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3 years ago
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Without using a calculator, choose the statement that best describes the value of the square root of 46
allochka39001 [22]

Answer:

The value of √46 is between 6.5 and 7.

Step-by-step explanation:

We can use perfect squares to solve this problem.

1² = 1

2² = 4

3² = 9

4² = 16

5² = 25

6² = 36

7² = 49

A square root reverses the squaring operation. Therefore, if we take the square root of 49, we will get 7.

So, because 46 fits in the interval 36 < 46 < 49, we can solve this problem.

√36 = 6

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√49 = 7

Therefore, using this information, we can see that clearly the value of 46 is closer to 49, meaning that the square root of 46 is between 6.5 and 7.

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3 years ago
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