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valentinak56 [21]
2 years ago
15

Jamar is planning to survey a company’s employees. He will ask employees how long they’ve worked for the company and how much th

ey are paid. Do you think this data set will be skewed left, skewed right, or symmetric? Explain why.
Mathematics
2 answers:
Viktor [21]2 years ago
8 0

Answer:

The data set would most likely be skewed right. The majority of employees would be paid an average amount, and only a few high-ranking employees would be paid significantly higher amounts. This data would result in a longer tail on the right with the majority of the data points on the left. In general, real-world situations are not symmetrical. This often occurs when one end of the range is bound by limits. In this case, the left side is bound by the minimum wage that must be paid to workers. On the right side, the president and other executives in the company probably don’t have a limit on their salaries.

Step-by-step explanation:

the plato answer

Salsk061 [2.6K]2 years ago
5 0

Answer: I believe skewed right

Step-by-step explanation:

Their is a higher chance that it is skewed right because new workers will be coming in while long term workers will be retiring meaning that more workers will be toward the left side of the graph making anyone who has worked longer for the company possible outliers, which drags the graph to the right making it skewed right

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Answer:

The probability is   \frac{6}{91} ≅ 0.0659

Step-by-step explanation:

Let's analyze the question.

There are 15 students in the 8th grade.

The students are randomly placed into three different algebra classes of 5 students each.

We are looking for the probability that Trevor, Terry and Evan will be in the same algebra class.

One possible way to solve this question is to think about the product probability rule.

We can use it because we are in an equiprobable space. (And  also the events are independent).

Let's set for example a class for Evan.

The probability that Evan will be in a class is 1

Then for Terry there are 4 places out of 14 that puts Terry in the Evan's class.

We write 1.\frac{4}{14}

Finally for Trevor there are 3 places out of the remaining 13 that puts Trevor in the same class with Evan and Terry.

Using the product rule we write :

1.\frac{4}{14}.\frac{3}{13}=\frac{6}{91}

The probability of the event is \frac{6}{91} ≅ 0.0659

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3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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