If A and B are equal:
Matrix A must be a diagonal matrix: FALSE.
We only know that A and B are equal, so they can both be non-diagonal matrices. Here's a counterexample:
![A=B=\left[\begin{array}{cc}1&2\\4&5\\7&8\end{array}\right]](https://tex.z-dn.net/?f=A%3DB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%262%5C%5C4%265%5C%5C7%268%5Cend%7Barray%7D%5Cright%5D)
Both matrices must be square: FALSE.
We only know that A and B are equal, so they can both be non-square matrices. The previous counterexample still works
Both matrices must be the same size: TRUE
If A and B are equal, they are literally the same matrix. So, in particular, they also share the size.
For any value of i, j; aij = bij: TRUE
Assuming that there was a small typo in the question, this is also true: two matrices are equal if the correspondent entries are the same.
Answer:
Step-by-step explanation:
<u>Equation Solving</u>
We are given the equation:
It's required to solve it for a.
Swap sides to have the letter on the left side:
Divide by 
:
Answer:
28
Step-by-step explanation:
i got my answer by dividing my answer and i got 28
Order of operations are:
<span>1. Parentheses (simplify inside 'em)
2. Exponents
3. Multiplication and Division (from left to right)
<span>4. Addition and Subtraction (from left to right)
So, on your first one:
Parentheses first:8(3+4)-2*8/(5-3)
8(7)-2*8/(2)
There are no exponents so multiplication and division:56-16/2
56-8
Finally, addition and subtraction:56-8=48
Your second problem is a bit more complicated but follows the same rules:
</span></span>
<span><span>
Parentheses first:</span></span>
<span><span>
Now, exponents. Even though they are inside parentheses, we can't go further until we simply those.
(64+81)/5
Now back to parentheses:(145)/5
Division:
145/5=29
Hope that helps</span></span>
