Enter the values to complete the input/output table for the function.

Mathematics

1 answer:

Artist 52 [7]3 years ago

3 0

Given function : 3x−6y=12.

We are given x : −2 0 4.

We need to find the values of y's for x=-2, x=0 and x=4.

Plugging x=-2 in the given equation, we get

3(-2)−6y=12

-6 - 6y = 12.

Adding 6 on both sides, we get

-6+6 - 6y = 12+6

-6y = 18.

Dividing by -6 on both sides, we get

y= -3.

On the same way, plugging x=0.

3(0)−6y=12

-6y =12.

y=-2.

Plugging x=4,

3(4)−6y=12

12 -6y = 12.

Subtracting 12 on both sides.

12-12 -6y = 12-12

-6y=0

y=0.

Therefore,

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