3 years ago

Find three consecutive integers such that 4 times the least integer is 8 times two less the greatest integer.

1 answer:

6 0

$least \: int = x \\ 4x = 8((x + 2) - 2) \\ 4x = 8x \\ 0 = 4x \\ 0 = x \\ numbers = 0 \: 1 \: 2$

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