In △ABC, m∠A=52°, c=11, and m∠B=19°. Find a to the nearest tenth.

Mathematics

1 answer:

Ugo [173]2 years ago

8 0

From the problem we have

In △ABC, m∠A=52°, c=11, and m∠B=19°.

Draw the diagram with the help of given information, (see the attached image)

Now using Sine Law in the Triangle ABC, we can write

Now from Triangle ABC , we can write

$\frac{a}{sin52}=\frac{11}{sin109} \\$

Now simplify , we get

$\Rightarrow a=\frac{11}{sin109}*sin52\\ \\ \Rightarrow a=\frac{11}{0.9455}*0.7880\\ \\ \Rightarrow a=9.1676 \approx 9.2\\$

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