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3 years ago

13

How do you solve this problem? I’m really stressed and don’t know how, can someone take me step by step through it? It’s really

hard for me

2 answers:

zhannawk [14.2K]3 years ago

6 0

256= (16)²
= (4²)²
= 4^4
4√256= 4^4

Marina CMI [18]3 years ago

4 0

The answer to 4\|256 is 4, since we can find the square root of 256, which is 16, we can find the square root of the square root, which is 4, so, 4^4 is 256 is your answer

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What is the steps to solving this equation |4-z|+10=1

sammy [17]

4-z+10=1
+4
-z+14=1
-14-14
-z=-13
Z=13

3 0

3 years ago

Which unit represents 0.01 liters

Neporo4naja [7]

The correct answer is (C) centilters

3 0

3 years ago

We want to construct a box with a square bottom, rectangular sides, and no top. We have exactly 10 ft2 of material for building

Iteru [2.4K]

Answer:

$V_m=3.74\ ft^2$

Step-by-step explanation:

<u>Maximization Using Derivatives</u>

We'll use the first derivative to find the extreme values of a function and then find the value of the independent variables to make the function maximum.

The first step is to produce a model that contains only one variable, take its first derivative and equal it to 0.

Assume a box with a square bottom and rectangular sides. Let's set the sides of the bottom square as x and the height of the box as y. The volume of the box is

$V=x^2y$

And the total side area is the sum of the bottom square plus the 4 side areas, each one being a rectangle of dimensions x and y. The area is

$A=x^2+4xy$

We know the total material used for the box is $10 ft^2$

$x^2+4xy=10$

Solving for y

$\displaystyle y=\frac{10-x^2}{4x}$

The expression for the volume will now be a function only of x:

$\displaystyle V=x^2\cdot \frac{10-x^2}{4x}$

$\displaystyle V=\frac{10x-x^3}{4}$

Taking the derivative of V

$\displaystyle V'=\frac{10-3x^2}{4}$

Equating to 0

$\displaystyle \frac{10-3x^2}{4}=0$

Solving for x

$\displaystyle x=\sqrt{\frac{10}{3}}=1.83$

$x=1.83\ ft$

Computing the second derivative:

$\displaystyle V''=\frac{-3x}{2}$

The second derivative is negative for any positive value of x, thus the extreme value of x is a maximum, and the largest volume of the box is

$\displaystyle V_m=\frac{10\cdot 1.83-1.83^3}{4}$

$V_m=3.74\ ft^2$

3 0

3 years ago

Create a table to find the third differences for the polynomial s^3 − s^2 +s for integer values of ss from −3 to 3.

evablogger [386]

Step-by-step explanation:

$f(s)=s^3-s^2$

at s = -3

$f(-3)=-3^3-(-3)^2=18$

at s = -2

$f(-2)=-2^3-(-2)^2\\\Rightarrow f(-2)=-12$

at s = -1

$f(-1)=-1^3-(-1)^2\\\Rightarrow f(-1)=-2$

at s = 0

$f(0)=0^3-0^2\\\Rightarrow f(0)=0$

at s = 1

$f(1)=1^3-1^2\\\Rightarrow f(1)=0$

at s = 2

$f(2)=2^3-2^2\\\Rightarrow f(2)=4$

at s = 3

$f(3)=3^3-3^2\\\Rightarrow f(3)=18$

First difference

$f(-2')=f(-2)-f(-3)=-12-18=-30$

$f(-1')=f(-1)-f(-2')=-2--12=10$

$f(0')=f(0)-f(-1)=0--2=2$

$f(1')=f(1)-f(0)=0-0=0$

$f(2')=f(2)-f(1)=4-0=4$

$f(3')=f(3)-f(2)=18-4=14$

Second difference

$f(-1'')=f(-1')-f(-2')=10--30=40$

$f(0'')=f(0')-f(-1')=-8-40=-48$

$f(1'')=f(1')-f(0')=-2--8=6$

$f(2'')=f(2')-f(1')=14-4=10$

Third difference

$f(0'')-f(-1'')=-8-40=48$

$f(1'')-f(0'')=-2--8=6$

$f(2'')-f(1'')=4--2=6$

$f(2'')-f(1'')=10-4=6$

18 -12 -2 0 0 4 18

-30 10 2 0 4 14

40 -8 -2 4 10

-48 6 6 6

6 0

4 years ago

Multiply (x-3)(4x+2) using distributive property. Select the answer choice using the correct distribution

Natalka [10]

Answer:

-6x-6

Step-by-step explanation:

(x-3)(4x+2)

youre going to multiply the first x by the next two numbers in the second (..)

so.

x times 4x= 4x

x times 2+ 2x

now you have 4x+2x

Now you do -3 times 4x and 2

you get -12x-6

put the equations together and get

4x+2x-12-6

common variables and get

-6x-6

4 0

3 years ago