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aliya0001 [1]
3 years ago
5

A 5.00 L air sample has a pressure of 107 kPa at a temperature of -50C. If the temperature is raised to 102C and the volume expa

nds to 7.00L, what will the new pressure be?
Mathematics
1 answer:
joja [24]3 years ago
7 0

Answer:

129.9 kPa

Step-by-step explanation:

The relationship between temperature T, volume V and pressure P is given by the ideal gas equation which is given as

K = PV/T where K is a constant such that were there is a change of temperature T₁, volume V₁ and pressure P₁ to  temperature T₂, volume V₂ and pressure P₂ then the relationship may be given

P₁V₁/T₁ = P₂V₂/T₂

where T is measured in ⁰K

T₁ = -50 + 273

= 223 ⁰K

T₂ = 102 + 273

= 379 ⁰K

5 × 107/223  = P₂ × 7/379

P₂ = 129.9 kPa

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3 years ago
15
Makovka662 [10]

Answer:

Option A ( -3/2 , \frac{-3\sqrt{3} }{2} )

Step-by-step explanation:

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(For Diagram, Please Find in attachment)

Now In Triangle OAB

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6 0
3 years ago
Using your calculator, find the proportion of observations from a standard normal distribution that satisfies the following stat
emmainna [20.7K]
<span>Look at your table for a Z value of 1.55. The numbers on the far left column are your z values. See the 1.5 row, then move over to the 0.05 column to make it 1.55.
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3 0
3 years ago
A box with an open top has vertical sides, a square bottom, and a volume of 108 cubic meters. if the box has the least possible
Colt1911 [192]
Let x be the height  of the  box and y be the length of one side of the base then:-

V = xy^2 = 108

x = 108/y^2

Surface area = y^2 + 4xy 
S = y^2 + 4y* 108/y^2
S = y^2 + 432/y
Finding the derivative:-
dS/dy  = 2y - 432/y^2  = 0
2y^3 = 432
y^3 = 216
y = 6 

Check if this gives a minimum value:-
second derivative = 2 + 864/y^3  which is positive so  minimum.

V = xy^2 = 108
36y = 108
y = 3

Answer :-  dimensions of the box is 3*6*6 metres


 
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3 years ago
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Answer:

I want to say the answer is D

Step-by-step explanation:

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