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WINSTONCH [101]
3 years ago
6

Write a compound inequality that represents the situation:

Mathematics
2 answers:
DochEvi [55]3 years ago
5 0
The answer is B
The keywords at least and at most mean that it has to be less than or equal to/more than or equal to.
There is no value for x that can satisfy the conditions for C
Dmitriy789 [7]3 years ago
5 0
X ≥ -6 and x ≤ 3
-6 ≤ x ≤ 3
Letter B
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Select the equations whose graphs are parallel to the graph of the equation y=23x+5.
iren [92.7K]

Answer:

2x-3y=9    and    4x-6y=30

Step-by-step explanation:

hello :  

note y=(2/3)x+5  no y=23x+5

2/3 is the slope....... all lines parallel to this line has same slope.

1)   2x-3y=9   means : 3y = 2x-9   divide by 3 : y=(2/3)x-3..same slope.

2)  4x-6y=30  means : 6y= 4x-30 divide by 6 : y=(4/6)x -30/6

but 4/6 = 2/3 so : y=(2/3)x-5..same slope.

6 0
3 years ago
Find the missing factor "B" that makes the following equality true.
Olenka [21]

Answer:

gguj

Step-by-step explanation:

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3 0
3 years ago
During the afternoon, and 18 foot tall tree casts a shadow 25 feet long. What is the approximate andle of elevation from the end
Karo-lina-s [1.5K]

a tree casts a 25-foot shadow on sunny day. If the angle of elevation from the tip of the shadow to the top of the tree is 32 degree, what is the height of the tree to the nearest tenth of a foot?

 

Tan(32)=H/25

0.624869=H/25

H=.624869 X 25

H=15.6 feet-Height of the tree.

6 0
3 years ago
Probabilities. Please help
Anon25 [30]

In throwing a dice, there are 6 possible outcomes, namely 1, 2, 3, 4, 5 and 6.

P=(no. of favourable outcomes)/(no. of possible outcomes)

When we multiply the probability of an event with no. of trials, the we get the expected frequency of that event.

1) P(getting 1)=1/6

expected frequency of getting 1

=P(getting)1)×no. of trials

=1/6×600=100

But it is given that one is scored 200 times, so it makes a large difference from expected frequency, which is 100.

Therefore, the dice is not fair.

2) P(getting a tail)=0.3

estimate for the number of times the coin will land on a tail

=expected frequency of getting a tail

=P(getting a tail)×no. of trials

=0.3×150=45

3)P(getting a six)=2/3

expected frequency of getting a six

=P(getting a six)×no. of trials

=2/3×300=200

4)P(getting a three)=0.5

expected frequency of getting a three

=P(getting a three)×350

=0.5×350=175

3 0
3 years ago
I need the explanation of answer #11. On the textbook answer key section is states that the answer to this problem is 300mph. I
Sergio [31]

Answer:

300 mph

Step-by-step explanation:

Let's say x is the speed of the plane in still weather.

The time it takes flying against the wind is:

990 mi / (x − 30 mph)

The time it takes flying with the wind is:

990 mi / (x + 30 mph)

The total time is 6⅔ hours, so:

6⅔ hr = 990 mi / (x − 30 mph) + 990 mi / (x + 30 mph)

6⅔ = 990  / (x − 30) + 990 / (x + 30)

20/3 = 990  / (x − 30) + 990 / (x + 30)

Solving this equation for x, multiply both sides by 3 (x − 30) (x + 30):

20 (x − 30) (x + 30) = 2970 (x + 30) + 2970 (x − 30)

20 (x² − 900) = 2970x + 8910 + 2970x − 8910

20x² − 18000 = 5940x

20x² − 5940x − 18000 = 0

x² − 297x − 900 = 0

Factor:

(x − 300) (x + 3) = 0

x = 300 or -3

Since x must be positive, x = 300 mph.

7 0
3 years ago
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