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Natali [406]
3 years ago
7

8.9 – 1.4x + (–6.5x) + 3.4

Mathematics
2 answers:
luda_lava [24]3 years ago
7 0

Answer:

12.3 – 7.9x

Step-by-step explanation:

the product of + and - is -

Therefore,

8.9 – 1.4x + (–6.5x) + 3.4

= 8.9 – 1.4x –6.5x + 3.4

collect like terms

= – 1.4x – 6.5x + 3.4 + 8.9

= –7.9x + 12.3

= 12.3 – 7.9x

Sphinxa [80]3 years ago
3 0
8.9 + 3.4 -1.4x - 6.5x = 12.3 - 7.9x
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A circle is centered at the point (5, -4) and passes through the point (-3, 2).
harina [27]

Answer:

The answer to your question is:

             (x - 5)² + (y + 4)² = 10²     or         (x - 5)² + (y + 4)² = 100

Step-by-step explanation:

Data

Center (5, - 4)

Point ( -3 , 2)

Formula

d = √ ((x2- x1)² + (y2 - y1)²)

(x - h)² + (y - k)² = r²

Process

Radius

d = √ ((-3 - 5)² + (2 + 4)²)

d = √ ((-8)² + (6)²)

d = √ 64 + 36

d = √100

d = 10 units

Circle

                           (x - 5)² + (y + 4)² = 10²

                             (x - 5)² + (y + 4)² = 100

8 0
3 years ago
Helpp ludzie pomocy bo gram cały czas na lekcjach (xd) a moja matka przyszła do haułpy ​
leonid [27]

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Step-by-step explanation:

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8 0
3 years ago
Select the correct answer. Which function has a domain of all real numbers? A.y=(x+2)^ 1/4 B.y=-x^ 1/2+5 C.y=-2(3x)^1/6 D.y=(2x)
BaLLatris [955]

Answer:

The answer is probably A

Step-by-step explanation:

Its domain is the only one of these that contain -2, which is a real number.

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The plutonium isotope has half life
ratelena [41]

Answer:

Step-by-step explanation:

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6 0
3 years ago
Which of the following can be used to calculate the volume of water inside the fish bowl?
Lunna [17]

The volume of a sphere can be calculated as

V=\frac{4}{3}\pi r^3

Where r is the radius of the sphere

We want to calculate half of the volume, then we must divide that volume by 2

V^{\prime}=\frac{1}{2}\frac{4}{3}\pi r^3

Now we must find the radius of our sphere, the segment AB is the diameter of the sphere, and the radius is half od the diameter, then

r=\frac{AB}{2}=\frac{12}{2}=6

Let's put it into our equation

\begin{gathered} V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)(\pi)(r)^3 \\  \\ V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)(\pi)(6)^3 \end{gathered}

The problem says to use

\pi\approx\frac{22}{7}

Then

V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)\left(\frac{22}{7}\right)(6)^3

Final answer:

The formula that can be used to calculate the volume of water inside the fish bowl is

V=\frac{1}{2}\left(\frac{4}{3}\right)\left(\frac{22}{7}\right)(6)^3

8 0
1 year ago
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