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3 years ago

Is x = 3 a solution to the inequality below? 5 ≥ x

Mathematics

2 answers:

Licemer1 [7]3 years ago

5 0

Answer:

yes

Step-by-step explanation:

5 is more than or equal to 3

3 makes the inequality true

plz mark me brainliest

Solnce55 [7]3 years ago

3 0

Answer:

No the answer would be x ≥ 5

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Dennis_Churaev [7]

Answer:

77$

Step-by-step explanation:

5 0

3 years ago

Whats the answer to this?

8_murik_8 [283]

6^7
-----
6^5
===
answer would be
6^2

4 0

3 years ago

Read 2 more answers

3.x4 - 2x2 + 15.x2<br> Which product Is the factored form of the polynomial

Dmitry_Shevchenko [17]

Answer:

3*4=12

12-2=10

10*2=20

20+15=35

35*2=70

Step-by-step explanation:

4 0

3 years ago

Elisa needs 40 shirts for a charity. One store is selling shirts for $6.95 each. Another store says that the total for al 40 shi

xxTIMURxx [149]

Well, let us figure out what the first store will cost.
40*6.95=278
Now for the second store
325*0.8=260

So the first store is $278, while the second store is $260, so Elisa should buy shirts from the second store

7 0

3 years ago

having trouble with this problem, pls help :/ I know the answer, just not how to get there. (ap calc ab, integrals)

pochemuha

Answer: D) 101

Step-by-step explanation:

By linearity, we can break it up into 2 integrals. The integral and derivative of f easily cancel out

$\int\limits^{10}_{-1} {(2x+0.5f'(x))} \, dx =\int\limits^{10}_{-1} {2x} \, dx +0.5\int\limits^{10}_{-1} {f'(x)} \, dx =x^2|^{^{10}}_{_{-1}}+0.5f(x)|^{^{10}}_{_{-1}}\\=(100-1)+0.5(f(10)-f(-1))=99+0.5(8-4))=101$

I used the table for values of f(x) at 10 and -1. Wouldn't be surprised if this was part of a series of questions about f because I really can't see how you could use the hypothesis that f is twice differentiable on R. Same for the other table values. I'm curious about how you found the answer. Was it a different way?

7 0

3 years ago