For Answer A, it is 3/4 because there are 4 donuts in total and you have 3 glazed and 1 chocolate, so it will be 3 over 4.
For Answer B, it is 75% because 3 over 4 is 0.75 and if you put it in percentage, then it will be 75%.
The total amount of people who ordered a large is 5 + 12 + 8 = 25 people.
The amount of customers who bought a large cold drink is 5.
The probability that someone bought a large cold drink is 5 out of 25 people.
This is 5/25 which is 1/5 which is .2
Convert the decimal to a fraction by multiplying by 100 and adding a percent sign at the end.
.2 x 100 = 20%
Edit:
The probability was supposed to be if the customer ordered a cold drink based on people who ordered large.
The amount of people who ordered a large drink is 22 + 5 = 27.
The amount of people who ordered a cold large is 5.
To find the percent, divide the people who ordered cold large by the total people who ordered large.
This would be 5/27 which in decimal form is .185185
To convert to a percent, multiply by 100 and add a percent sign after it.
.185185 x 100 = 18.5185%
The question says to round to the nearest percent so your answer is:
19%
Recall that A = 1/2bh.
We are given that h = 4+2b
So, putting it all together:
168 = 1/2 b(4+2b)
168 = 1/2(4b + 2b^2)
168 = 2b + b^2
b^2 + 2b - 168 = 0.
Something that multiplies to -168 and adds to 2? There's a trick to this.
Notice 13^2 = 169. So, it's more than likely in the middle of the two numbers we're trying to find. So let's try 12 and 14. Yep. 12 x 14 = 168. So this factors into (b+14)(b-12) So b = -14 or b =12. Is it possible to have a negative length on a base? No. So 12 must be our answer.
Let's check this. If 12 is our base, then according to our problem, 2*12 + 4 would be our height... or 28. so what is 12 * 28 /2?
196. Check.
Hope this helped!
Answer:
Step-by-step explanation:
Consider the revenue function given by 
. We want to find the values of each of the variables such that the gradient( i.e the first partial derivatives of the function) is 0. Then, we have the following (the explicit calculations of both derivatives are omitted).
From the first equation, we get, 
.If we replace that in the second equation, we get
From where we get that 
. If we replace that in the first equation, we get
So, the critical point is 
. We must check that it is a maximum. To do so, we will use the Hessian criteria. To do so, we must calculate the second derivatives and the crossed derivatives and check if the criteria is fulfilled in order for it to be a maximum. We get that
We have the following matrix,
![\left[\begin{matrix} -10 & -2 \\ -2 & -16\end{matrix}\right]](https://tex.z-dn.net/?f=%20%5Cleft%5B%5Cbegin%7Bmatrix%7D%20-10%20%26%20-2%20%5C%5C%20-2%20%26%20-16%5Cend%7Bmatrix%7D%5Cright%5D)
.
Recall that the Hessian criteria says that, for the point to be a maximum, the determinant of the whole matrix should be positive and the element of the matrix that is in the upper left corner should be negative. Note that the determinant of the matrix is 
and that -10<0. Hence, the criteria is fulfilled and the critical point is a maximum
Answer:
it's D
Step-by-step explanation:
i just know what I am talking about
