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7nadin3 [17]
3 years ago
14

On March​ 1, Year​ 1, LuxWear Inc. had beginning inventory and​ purchases, at​ cost, of​ $50,000 and​ $20,000, respectively. The

beginning inventory and purchases had a retail value of​ $75,000 and​ $30,000, respectively. The company had sales of​ $60,000, as well as markups of​ $6,000 and markdowns of​ $10,000. What would LuxWear report as the lower of cost or market for its ending inventory on March​ 31, Year 1 using the conventional​ (LCM) retail​ method? (Round the​ cost-to-retail ratio to two decimal​ places.)
Business
1 answer:
Tcecarenko [31]3 years ago
6 0

Answer: $25,830

Explanation:

Description

Cost

Retail

Beginning inventory

$50,000

$ 75,000

Purchases

20,000

30,000

Markups

0

6,000

Subtotal

$70,000

$111,000

Cost-to-retail ratio:

$70,000/$111,000 = 63%

Markdowns

0

(10,000)

Goods available for sale

$70,000

$101,000

Less: Sales at retail

(60,000)

Ending inventory at retail

$ 41,000

Ending inventory at lower of cost or market:

$41,000 x 63% =

$25,830

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<h3>Low-cost / low-price advantage </h3>

It results in high profit only if;

  • (1) prices are reduced by less than the size of the cost advantage or
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1. B. Journalize the transactions for May, starting on Page 20 of the journal.*
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Answer:

Rent Expense (Dr.) $5,000

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Cost of Goods Sold (Dr.) $48,500

Inventory (Cr.) $48,500

Explanation:

Advertising Expense (Dr.) $21,800

Cash (Cr.) $ 21,800

Cash (Dr.) $62,000

Accounts Receivable Korman Co. (Cr.) $62,000

Customer Refund Payable (Dr.) $31,500

Cash (Cr.) $31,500

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8 0
3 years ago
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$4,000

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P- percent

r-rate

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Because of the relatively high interest rates, most consumers attempt to pay off their credit card bills promptly. However, this
telo118 [61]

Answer:

a) Proportion = 41.3%

b) Proportion = 9.18%

c) Proportion = 13.35%

d) Interest payment = $37.28

Explanation:

We have normal distribution with mean = 29 and standard deviation = 9

a) The proportion of the bank’s Visa cardholders pay more than $31 in interest is:

P(X > 31) = (\frac{X-29}{9}>\frac{31 -29}{9}) = P (Z > 0.22) = 1 - P (Z ≤ 0.22) =  

1 - 0.58706 = 0.41294 = 41.3%

The proportion of the bank's Visa cardholders pay more than 31 dollars in interest is 41.3%.

b) The proportion of the bank’s Visa cardholders pay more than $31 in interest is:

P(X > 41) = (\frac{X-29}{9}>\frac{41 -29}{9}) = P (Z > 1.33) = 1 - P (Z ≤ 1.33) =  

1 - 0.90824 = 0.09176 = 9.176% ≈ 9.18%

The proportion of the bank's Visa cardholders pay more than 31 dollars in interest is 9.18%.

c) The proportion of the bank’s Visa cardholders pay more than $31 in interest is:

P(X > 19) = (\frac{X-29}{9}>\frac{19 -29}{9}) = P (Z < -1.11) = 1 - P(Z ≤ -1.11)) =0.13350 = 13.35%

The proportion of the bank's Visa cardholders that paid less than 19 dollars in interest is 13.35%.

d) Let's suppose this amount of payment is Y:

Therefore P(X > Y) = 0.18

so P(X < Y) = 0.82

Utilizing standard normal approximation

P(X ≤ Y) = (\frac{X-29}{9}\leq \frac{Y -29}{9}) = P (Z ≤ \frac{Y-29}{9})  =  0.82

Form the standard normal table we find that \frac{Y-29}{9} = 0.92

Therefore,

Y - 29 = 9×0.92

Y - 29 = 8.28

Y = 8.28 + 29 = 37.28

Therefore $37.28 of interest payment is exceeded by only 18% of the bank's Visa cardholders.

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