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Contact [7]
3 years ago
10

Atoms that have become negatively charged by gaining extra electrons are called _____. anions anodes cations cathodes

Physics
2 answers:
Archy [21]3 years ago
7 0

Answer:

Anions

Explanation:

Anions : Anions are defined as the atoms or the radicals. Atoms that have become negatively charged by gaining extra electrons are anions. For example, bromide ion (Br⁻), chloride ion (Cl⁻).

Anodes : The positively charged electrode by which an electron leave a device is called an anode.

Cations : They are the positively charged particle. For example silver ion (Ag⁺).

Cathodes : The negatively charged electrode by which an electron enter an device is called an cathodes.

Hence, the correct option is (a) " anions ".

nikklg [1K]3 years ago
5 0
Anions: negatively charged atoms

Cations: positively charged atoms (CAT-ions are PAWS-itively charged)
Anode: positively charged electrode that allows electrical current flow (positive end of battery)
Cathode: negatively charged electrode that allows electrical current flow (negative end of batter)
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A man pushes a stalled car with a force of 100 N. If the acceleration of the car is 0.75 m/s 2 , what is the mass of the car?
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A 4.7-kg solid sphere, made of metal whose density is 4000 kg/m3, hangs by a light cord. When the sphere is immersed in water, w
lara31 [8.8K]

Answer:

T = 34.54 N

Explanation:

First we find the buoyant force acting on the sphere, due to displaced water. For that purpose, we need to find the volume of water displaced by the sphere.

Volume of Water Displaced = V = (Mass of Sphere)/(Density of metal)

V = 4.7 kg/(4000 kg/m³)

V = 0.001175 m³

Now, the buoyant force is given as:

F = (Density of Water)(V)(g)

F = (1000 kg/m³)(0.001175 m³)(9.8 m/s²)

F = 11.52 N

Now, we find the weight of the sphere:

W = mg = (4.7 kg)(9.8 m/s²)

W = 46.06 N

Since, both the tension force (T) and buoyant force act in upward direction, while the weight of sphere act in downward direction. Therefore,

W = T + F

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4 0
3 years ago
Astronauts on the first trip to Mars take along a pendulumthat has a period on earth of 1.50 {\rm s}. The period on Mars turns o
svetlana [45]

Answer:

3.7 m/s^2

Explanation:

The period of a simple pendulum is given by:

T=2 \pi \sqrt{\frac{L}{g}}

where L is the length of the pendulum and g is the free-fall acceleration on the planet.

Calling L the length of the pendulum, we know that:

T_e = 2 \pi \sqrt{\frac{L}{g_e}}=1.50 s is the period of the pendulum on Earth, and g_e = 9.8 m/s^2 is the free-fall acceleration on Earth

T_m = 2 \pi \sqrt{\frac{L}{g_m}}=2.45 s is the period of the pendulum on Mars, and g_m = ? is the free-fall acceleration on Mars

Dividing the two expressions we get

\frac{T_e}{T_m}=\sqrt{\frac{g_m}{g_e}}

And re-arranging it we can find the value of the free-fall acceleration on Mars:

g_m = g_e \frac{T_e^2}{T_m^2}=(9.8 m/s^2)\frac{(1.50 s)^2}{(2.45 s)^2}=3.7 m/s^2

4 0
3 years ago
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