Ask question

Ask question

All categories

3 years ago

7

Matthew throws a ball straight up into the air. It rises for a period of time and then begins to drop. At which points in the ba

ll's journey will
gravity be the greatest force acting on the ball?

1 answer:

mars1129 [50]3 years ago

7 0

Answer:

Matthew throws a ball straight up into the air. It rises for a period of time and then begins to drop. At which points in the ball's journey will

gravity be the greatest force acting on the ball?

Explanation:

You might be interested in

An object is formed by attaching a uniform, thin rod with a mass of mr = 6.85 kg and length L = 5.76 m to a uniform sphere with

Ket [755]

Answer:

Part a)

$I = 1879.7 kg m^2$

Part b)

$\alpha = 0.70 rad/s^2$

Part c)

$I = 153.8 kg m^2$

Part 4)

angular acceleration will be ZERO

Part 5)

$I = 345.6 kg m^2$

Explanation:

Part a)

Moment of inertia of the system about left end of the rod is given as

$I = \frac{m_r L^2}{3} + (\frac{2}{5} m_s R^2 + m_s(R + L)^2)$

So we have

$I = \frac{m_r(4R)^2}{3} + (\frac{2}{5}(5m_r) R^2 + (5m_r)(R + 4R)^2)$

$I = \frac{16}{3}m_r R^2 + (2m_r R^2 + 125 m_rR^2)$

$I = (\frac{16}{3} + 127)m_r R^2$

$I = (\frac{16}{3} + 127)(6.85)(1.44)^2$

$I = 1879.7 kg m^2$

Part b)

If force is applied to the mid point of the rod

so the torque on the rod is given as

$\tau = F\frac{L}{2}$

$\tau = 460(2R)$

$\tau = 460 \times 2 \times 1.44$

$\tau = 1324.8 Nm$

now angular acceleration is given as

$\alpha = \frac{\tau}{I}$

$\alpha = \frac{1324.8}{1879.7}$

$\alpha = 0.70 rad/s^2$

Part c)

position of center of mass of rod and sphere is given from the center of the sphere as

$x = \frac{m_r}{m_r + m_s}(\frac{L}{2} + R)$

$x = \frac{m_r}{6 m_r}(3R) = \frac{R}{2}$

so moment of inertia about this position is given as

$I = \frac{m_r L^2}{12} + m_r(\frac{L}{2} + \frac{R}{2})^2 + (\frac{2}{5} m_s R^2 + m_s(\frac{R}{2})^2)$

so we have

$I = \frac{m_r (16R^2)}{12} + m_r(\frac{5R}{2})^2 + \frac{2}{5}(5m_r)R^2 + (5m_r)(\frac{R^2}{4})$

$I = m_r R^2(\frac{16}{12} + \frac{25}{4} + 2 + \frac{5}{4})$

$I = 6.85(1.44)^2\times 10.83$

$I = 153.8 kg m^2$

Part 4)

If force is applied parallel to the length of rod

then we have

$\tau = \vec r \times \vec F$

$\tau = 0$

so angular acceleration will be ZERO

Part 5)

moment of inertia about right edge of the sphere is given as

$I = \frac{m_r L^2}{12} + m_r(\frac{L}{2} + 2R)^2 + (\frac{2}{5} m_s R^2 + m_s(R)^2)$

so we have

$I = \frac{m_r (16R^2)}{12} + m_r(4R)^2 + \frac{2}{5}(5m_r)R^2 + (5m_r)(R^2)$

$I = m_r R^2(\frac{16}{12} + 16 + 2 + 5)$

$I = 6.85(1.44)^2\times 24.33$

$I = 345.6 kg m^2$

6 0

3 years ago

The amount of work done by a heat engine equals the amount of thermal energy _____. added to the engine plus the waste heat adde

RideAnS [48]

added to the engine minus the waste heat

Explanation:

The amount of work done by a heat engine equals the amount of thermal energy added to the engine minus the waste heat.

Thermodynamics is used to measure the energy changes that accompanies physical and chemical process.

In a system;

Internal energy = Quantity of heat added - Work done on it

internal energy is designated as ΔU

quantity of heat as Q

work done as W

ΔU = Q - W

so W = Q - ΔU

some of the heat added added to the system goes as waste heat as no system is 100% efficient.

the work done on a system goes in as thermal energy, internal energy and waste heat

learn more:

Thermodynamics brainly.com/question/3564634

#learnwithBrainly

3 0

3 years ago

Fossil fuels are burned, transferring their chemical potential energy to heat energy. How are nuclear power stations different?

labwork [276]

Answer:

fossil fuels are natural and limited, nuclear is man made and more toxic

Explanation:

6 0

3 years ago

The purpose of any simple machine is to allow a job to be done with less force than would normally be needed. However, when a st

Black_prince [1.1K]

The essay will highlight the fact that for every simple machine, there is always friction involved. As per the law of conservation of energy, the energy input to a system is equivalent to the energy output. Some of this output is in the form of friction, which is not useful. As the moving parts in a machine increase, it becomes more complex and more friction is generated between its parts. Therefore, a complex machine ends up being less efficient.

6 0

3 years ago

Match the terms to the correct descriptions.

Ulleksa [173]

2. kinetic energy: due to it being transferred through collisions

5 0

3 years ago

Read 2 more answers