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3 years ago

Please help! This is due today!

Mathematics

1 answer:

avanturin [10]3 years ago

3 0

Answer:

Z = 70

Step-by-step explanation:

14×25 = 5z

350 = 5z

Z = 350/5

Z = 70

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8+9=

Bumek [7]

Answer:

Step-by-step explanation:

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3 years ago

9x-8>4x+7 solve the linear inequality

allochka39001 [22]

$9x-8>4x+7$

Move the "x" terms to the right

$9x-4x>7+8$ $5x>15$

Divide both sides by 5:

$\frac{5x}{5}>\frac{15}{5}$ $x>3$

7 0

1 year ago

A car travels a distance of 190 miles in a time of 3.4 hours.

Dima020 [189]

Answer:

His average speed was 55.8 miles per hour

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3 years ago

Read 2 more answers

Brandon and Nolan work at a furniture store. Brandon is paid $235 per week plus 6% of his total sales in dollars, x, which can b

Helen [10]

The value of "x" is 14400 dollars that will make their weekly pay the same

Solution:

Given that,

Brandon is paid $235 per week plus 6% of his total sales in dollars, x, which can be represented by g (x) =235 + 0.06x

g(x) = 235 + 0.06x ----- eqn 1

Nolan is paid $667 per week plus 3% of his total sales in dollars, x, which can be represented by f(x ) = 667 + 0.03x

f(x) = 667 + 0.03x ----------- eqn 2

Determine the value of x, in dollars, that will make their weekly pay the same

For their weekly pay to be same, g(x) = f(x)

235 + 0.06x = 667 + 0.03x

Move the variables to one side and constants to other side

0.06x - 0.03x = 667 - 235

0.03x = 432

x = 14400

Thus value of "x" is 14400 dollars that will make their weekly pay the same

6 0

3 years ago

The proportion of households in a region that do some or all of their banking on the Internet is 0.31. In a random sample of 100

Alenkasestr [34]

Answer:

Approximate probability that the number of households that use the Internet for banking in a sample of 1000 is less than or equal to 130 is less than 0.0005% .

Step-by-step explanation:

We are given that let X be the number that do some or all of their banking on the Internet.

Also; Mean, $\mu$ = 310/1000 or 0.31 and Standard deviation, $\sigma$ = 14.63/1000 = 0.01463 .

We know that Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

Probability that the number of households that use the Internet for banking in a sample of 1000 is less than or equal to 130 is given by P(X <= 130/1000);

P(X <=0.13) = P( $\frac{X-\mu}{\sigma}$ <= $\frac{0.13-0.31}{0.01463}$ ) = P(Z <= -12.303) = P(Z > 12.303)

Since this value is not represented in the z table as the value is very high and z table is limited to x = 4.4172.

So, after seeing the table we can say that this probability is approximately less than 0.0005% .

4 0

3 years ago