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MrRissso [65]
3 years ago
8

Need help ASAP i am timed

Mathematics
1 answer:
Nadya [2.5K]3 years ago
8 0
A
B
Just search it up on a math website or sum
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A pack of paper costs $3.75 including tax. Mr. Cooper wants to purchase packs of paper for his class and has a $20 budget. Write
Anastaziya [24]
The answer is a because it’s showing that he spends 3.75$ on each sheet of paper and x represents how many he can buy. It also shows that it can be less or equal to 20$
7 0
2 years ago
What is the remainder when the product of the 5 smallest prime numbers is divided by 42?
sveta [45]

Answer:

0

Step-by-step explanation:

The five smallest prime numbers are 2, 3, 5, 7 and 11.

2 × 3 × 5 × 7 × 11

= 2310

Divide by 42.

2310/42

= 55, Remainder 0

5 0
3 years ago
I need help.<br><br> someone help please!
Vikentia [17]
Sorry, I think there is missing context?
4 0
3 years ago
Read 2 more answers
Assume that the probability of a defective computer component is 0.02. Components arerandomly selected. Find the probability tha
solmaris [256]

Answer:

0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.

The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.

Step-by-step explanation:

Assume that the probability of a defective computer component is 0.02. Components are randomly selected. Find the probability that the first defect is caused by the seventh component tested.

First six not defective, each with 0.98 probability.

7th defective, with 0.02 probability. So

p = (0.98)^6*0.02 = 0.0177

0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.

Find the expected number and variance of the number of components tested before a defective component is found.

Inverse binomial distribution, with p = 0.02

Expected number before 1 defective(n = 1). So

E = \frac{n}{p} = \frac{1}{0.02} = 50

Variance is:

V = \frac{np}{(1-p)^2} = \frac{0.02}{(1-0.02)^2} = 0.0208

The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.

5 0
2 years ago
CAN SOMEONE HELP:) PLSSS
rewona [7]

Answer:

I honestly don’t know I am gonna guess

Step-by-step explanation:

1/12?

. 。 •  ゚ 。  . .

 . .  。 。 . .

. 。 ඞ 。 . •  • .

.

゚ Bread was Not An Impostor. 。 . .

' 1 Impostor remains  。 .

゚  .  . , . .. . .

Have a nice day UwU

6 0
2 years ago
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