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3 years ago

Question 20

1 answer:

5 0

The main advantage of the metric system and it's use is that it Does not require knowledge of math to use it. A person having non or low level of knowledge can use it.

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The length of a rectangle is 1 inch shorter than twice the width (x).Which is the width (x) when the area (y) = 3321 square inch

zlopas [31]

the width (x) of the rectangle = 41 inches

Explanation:

let the width = x

twice the width = 2x

The length of a rectangle is 1 inch shorter than twice the width (x) = 2x - 1

length = 2x -1

Area of rectangle = length × breadth

area (y) = 3321 square inches

y = x × 2x - 1 = x(2x - 1)

3321 = 2x² - x

2x² - x - 3321 = 0

We use factorisation to find x:

a = 2, b = -1, c = -3321

a × c = 2(-3321) = -6642

The factors which gives -1 when we sum together but gives -6642 when we multiply together are -82 and +81

2x² -82x + 81x - 3321 = 0

2x(x - 41) + 81(x - 41) = 0

(2x + 81) (x - 41) = 0

(2x + 81) = 0 or (x - 41) = 0

2x + 81 = 0

2x = -81

x = -81/2 inches

(x - 41) = 0

x - 41 = 0

x = 41 inches

Since we can't have a negative number as the width, the width (x) of the rectangle = 41 inches

4 0

1 year ago

Examine the system of equations at right. y=-2x + 6 y = -9

zubka84 [21]

Answer: -6

Step-by-step explanation: y-intercept: Put x = 0 in the equation y = 2x - 6 and solve for x. The y-intercept is -6

Hope This Helps Dude

5 0

4 years ago

Which is the best estimate of the mass of a skateboard.

Dahasolnce [82]

Answer:

3 kilograms

Step-by-step explanation:

one is for liquids and the others are too small i think

8 0

3 years ago

Find the total surface area of this cuboid

Tanya [424]

Answer:

143.5 =1 decimal point

Step-by-step explanation:

7 0

3 years ago

For a sample of eight bears, researchers measured the distances around the bears' chests and weighed the bears. Minitab was us

Yakvenalex [24]

Answer:

There is a linear correlation between the chest size and weight

Proportion of the variation in weight can be explained by the linear relationship between weight and chest size is 0.006724 .

Step-by-step explanation:

Null Hypothesis: $H_0$ = There is no linear correlation between the chest size and weight

Alternative Hypothesis : $H_a$ =There is a linear correlation between the chest size and weight

The value of the linear correlation coefficient is r=0.882.

n = 8

Formula : $t=\frac{r\sqrt{n-2}}{\sqrt{1-r^2}}$

$t=\frac{0.882\sqrt{8-2}}{\sqrt{1-(0.882)^2}}$

$t=4.584$

Degree of freedom = n-1 = 8-1 = 7

α =0.05

so, p value is 2.365

t calculated > t critical

So, we reject the null hypothesis

So, There is a linear correlation between the chest size and weight

The proportion of the variation in weight can be explained by the linear relationship between weight and chest size = $r^2 = (0.082)^2=0.006724$

Hence proportion of the variation in weight can be explained by the linear relationship between weight and chest size is 0.006724 and There is a linear correlation between the chest size and weight

4 0

3 years ago