The two variables are time (x) and distance (y)
And the answer is they will meet after 1 mile
The function of the aunt and uncle is y=25x+5
The function of yourself is y2=30x
Since you want to know when you’ll meet, you just resolve y=y2 or 25x+5=30x
Wich will be x=1 so 1 mile
Answer:shipping box=3.75*3*3.25=36.562 cubic feet.in width we have 15 cubes,in the legnt 12 while in height 13.with a total of 2340 cubes
Step-by-step explanation:
Answer:
Do you have a diagram? I cant help you if you have a diagram.
Step-by-step explanation:
Answer:
Student 2 and Student 3
Step-by-step explanation:
Student 2
-(5r - 3s + 1)
= - 5r +3s - 1
Student 3
= - 5r +3s - 1
Answer:
<h2>B. x = -1, x = -3, y = 0</h2>
Step-by-step explanation:
