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3 years ago

14

Brianna wants to buy a digital camera for a photography class. One store offers the camera for $53 down and a payment plan of $1

9 per month. The payment plan for a second store is described by y = 15x + 76, where y is the total cost in dollars and x is the number of months. Which camera is cheaper when the camera is paid off in 12 months? Complete the explanation.

1 answer:

Basile [38]3 years ago

7 0

Answer:

The second store is cheaper in 12 months.

Step-by-step explanation: do 53+19(12), which is 281 for store one at 12 months. Do 73+15(12), which is 253 at 12 months. If you compare it, the second store is cheaper

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HELP ASAP WILL MARK BRAINLIEST AREA OF FIGURES

Lerok [7]

Answer:

1. 170.083 in³

2. 126π in³

3. 92.106 m³

4. 2412.74 in³

5. 612π m³ and 1922 m³

Step-by-step explanation:

1.

Cylinder:

$V = \pi r^{2}h$ *Plug in numbers*

$(3.14)(2.5)^{2}(7)$ *Square 2.5*

$(3.14)(6.25)(7)$ *Solve*

≈ $137.375in^{3}$

Sphere:

$V = \frac{4}{3}\pi r^{3}$ *Plug in numbers*

$\frac{4}{3} (3.14)(2.5)^{3}$ *Cube 2.5*

$\frac{\frac{4}{3}(3.14)(15.625)}{2}$ *Divide by 2 and Solve*

≈ $32.7083 in^{3}$

Add both volumes

$137.375 + 32.7083$ ≈ $170.083in^{3}$

2.

Cylinder:

$V = \pi r^{2}h$ *Plug in numbers*

$\pi (3)^{2}(10)$ *Square 3*

$\pi (9)(10)$ *Multiply*

$90\pi$

Sphere:

$V = \frac{4}{3}$ π $r^{3}$ *Plug in numbers*

$\frac{4}{3}\pi (3)^{3}$ *Cube 3*

$\frac{4}{3} \pi (27)$ *Multiply*

$36\pi$

Add both Volumes to get total

$90\pi + 36\pi = 126in^{3}$

3.

Sphere:

$V = \frac{4}{3}\pi r^{3}$ *Plug in numbers*

$\frac{4}{3} (3.14)(3)^{3}$ *Cube 3*

$\frac{4}{3} (3.14)(27)$ *Multiply*

$113.04m^{3}$

Cone:

$V = \frac{\pi r^{2}h}{3}$ *Plug in numbers*

$\frac{(3.14)(2)^{2}(5)}{3}$ *Square 2*

$\frac{(3.14)(4)(5)}{3}$ *Solve*

$20.93m^{3}$

Subtract the volumes to get the volume of the blue area

$113.04 - 20.93 = 92.106m^{3}$

4.

Sphere:

$V = \frac{4}{3} \pi r^{3}$ *Plug in numbers*

$\frac{4}{3}\pi (8)^{3}$ *Cube 8*

$\\\frac{4}{3}\pi (512)$ *Multiply*

$\\\\\pi (682.6)$ *Solve*

$2133.66in^{3}$ *Divide by 2 since it's a hemisphere*

Cone:

$V = \frac{\pi r^{2}h}{3}$ *Plug in numbers*

$\frac{\pi (8)^{2}(20)}{3}$ *Square 8*

$\frac{\pi (64)(20)}{3}$ *Multiply and Divide*

$1340.41 in^{3}$

Add both volumes

$1072.33 + 1340.41 = 2412.74in^{3}$

5.

Cylinder:

$V = \pi r^{2}h$ *Plug in numbers*

$\pi (6)^{2}(16)$ *Square 6*

$\pi (36)(16)$ *Multiply*

$576\pi$

Cone:

$V = \frac{\pi r^{2}h}{3}$ *Plug in numbers*

$\frac{\pi (6)^{2}3}{3}$ *Square 6*

$36\pi$

Add both volumes

$576\pi + 36\pi = 612\pi m^{3}$

Alternative: *Multiply π*

$1922m^{3}$

4 0

3 years ago

Read 2 more answers

Jill leaves work from the High School, but has to pick up her friend at the airport before going back home. What is the shortest

Romashka-Z-Leto [24]

Answer:

21 miles

Step-by-step explanation:

That is just the answer I got.

3 0

3 years ago

Use a shortcut method of your choice to complete the multiplication problems.

Flura [38]

Answer:

See below.

Step-by-step explanation:

a. 973 * 80

= 973 * 8 * 10

= 7784 * 10

= 77,840.

b. 56 * 2000

= 2*56 * 1000

= 112,000.

c. 5.7 * 300

= 5.7 * 3 * 100

= 17.1 * 100

= 1710.

d. 0.46 * 50

= (0.46 * 100) / 2

= 46 / 2

= 23.

4 0

4 years ago

Read 2 more answers

The length of the longer leg of a right triangle is

Harman [31]

A and b are legs
a^2+b^2=c^2
lets say
a>b

so
a=13+3b
c=14+3b

a^2+b^2=c^2
(13+3b)^2+b^2=(14+3b)^2
9b^2+78b+169+b^2=9b^2+84b+196
10b^2+78b+169=9b^2+84b+196
minus 9b^2 both sides
b^2+78b+169=84b+196
minus 84b both sides
b^2-6b+169=196
minus 196 both sides
b^2-6b-27=0
factor
(b+3)(b-9)=0
set to zero
b+3=0
b=-3, false, dimentions cannot be negative

b-9=0
b=9

shorter leg is 9

a=13+3b
a=13+3(9)
a=13+27
a=40

c=14+3b
c=14+27
c=41

side legnths are
9in, 40in, 41in

3 0

3 years ago

What is the inverse of the function below? f(x) = 5x - 2

kupik [55]

Answer:

B. f -1(x) = x + 2 / 5

$f^{-1}(x)=\frac{x+2}{5}$

Step-by-step explanation:

To find the inverse of a function we need to interchange x and y an solve for y.

Since $f(x)=y$ , then

$f(x)=5x-2$

$y=5x-2$

$x=5y-2$

Add 2 to both sides

$x+2=5y-2+2$

$x+2=5y$

Divide both sides by 5

$\frac{x+2}{5}=\frac{5y}{5}$

$\frac{x+2}{5}=y$

$y=\frac{x+2}{5}$

$f^{-1}(x)=\frac{x+2}{5}$

We can conclude that the correct answer is B. f -1(x) = x + 2 / 5

6 0

3 years ago